Answer / prashanth

For Slab-arround 75 kgs/Cum steel will consume.
ie Vol=Mass/Density
=75/7850
= .0095
For one Cum includes (Concrete and Steel)
ie =1-.0095
=.99 (Concrete)
Then ratio=.0095/.99
=.00955 X 100
=.95 (Ratio between concrete and steel)

For Beam-arround 130 kgs/Cum steel will consume.
ie Vol=Mass/Density
=130/7850
= .0165
For one Cum includes (Concrete and Steel)
ie =1-.0165
=.983 (Concrete)
Then ratio=.0165/.983
=.0167 X 100
=1.67 (Ratio between concrete and steel)

For Beam-arround 150 kgs/Cum steel will consume.
ie Vol=Mass/Density
=150/7850
= .0191
For one Cum includes (Concrete and Steel)
ie =1-.0165
=.98 (Concrete)
Then ratio=.0191/.98
=.0194 X 100
=1.94 (Ratio between concrete and steel)

Answer / prem

Min amount of steel : based on concrete volume

Slab- 0.7 - 1
Beam 1- 3
Column 1-7
Footing 0.5 -8 percentage

Answer / basel

Concrete building element
Weight of reinforcement in kg/m3
Bases 90-130
Beams 250-350
Capping beams 135
Columns 200-450
Ground beams 230-330
Footings 70-100
Pile Caps 110-150
Plate slabs 95-135
Rafts 115
Retaining walls 110-150
Ribbed floor slabs 80-120
Slabs – one way 75-125
Slabs – two way 67-135
Stairs 130-170
Tie beams 130-170
Transfer slabs 150
Walls – normal 70-100
Walls – wind 90-150

NOTE: For exposed elements add the following:
Beams +100%; Columns +15%; Walls +50%

Average values for typical concrete frames:
Heavy industrial = 130 kg/m3
Commercial = 100 kg/m3
Institutional = 90 kg/m3

Answer / a

the ratio of steel and concrete to use in slabs ,
beams, columns are best grad is 1:1.5:3

Answer / karthikkannan n

For steel ratio is 90 kg/cum of concrete. It may vary depends upon the design considerations.

Providing and fixing in position Tor steel to footings, foundation, slabs, beams, columns, canopies, stair case, newels, chajjas, lintels, etc. including cutting, bending, hooking the bars, binding with wires. give me the rate M.ton.

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