Answer / swathi

A

Answer / ans

let ronit's present age be x
the father's age will be =x+3x=4x
after 8 years-4x+8=5/2(x+8)
3x=24
x=8
therefpre,required ratio is 4x+16/x+16= 48/2=2
so option A is correct!

Answer / charan

it is 2.2 times.Suppose rohit's age is 24, then his
father's age is 24*3=72. after 8 years rohit's father is 80
& rohit's 32 which is 2.5 times more. after 8 more years
father's age is 88 and rohit's 40 which is 2.2 times more

Answer / vignesh

You can also solve this problem by taking son's age as x and father's age as y. First, y = 4x as it is 3 times 'more' than that of his son. Then after 8 years son's age will be x+8 and father's age will be y+8=5/2(x+8) after solving you will get x = 8 and y = 32. Then after 16 years let father be n times of son's age i.e.
y + 16 = n(x + 16).
or 32 + 16 = n(8 + 16)
[putting x = 8 and y = 32]
or 48 = 24n,
or n = 2.
Therefore father is 2 times his son's age after 16 years.

Answer / sindhu

father=f and his son=s
f=3s
after 8 years,
f+8=2.5(s+8)
sub f=3s
3s+8=2.5(s+8)
s=24 and f=72
further 8 years,
s=32 and f=80
so ans is 2 and half times

Answer / anand

Ronit's age is X.
His father's age is 3x.

After 8 years

5/2(x+8)=(3x+8)
5(x+8)=2(3x+8)
5x+40=6x+16
x=24

Ronit's age after 16 years is X+8+8=40
His father's age is 3x+8+8=88
he would be 2+1/5 time of ronit's age.
I dont know whether it is right or wrong. But when i
multiply ronit age(after 16yrs) with 2+1/5 is equql to his
father's age(after 16 yrs).

Everyone said that father is aged 3 time more than his son
ronit, so that only you all take 4x instead of 3x, why cant
you take it as 5x , it is also more than 3 na.

Answer / ahmad khan

remember friend this is aptitude question .......



so answer is 3time

father's age and son's age difference will always be the same as the during son's birth. So that the age difference always be 3time difference

Answer / keshav talwar

the answer is 2 1/2 times

Answer / keshav talwar

2 3/4 times

Answer / shar

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