Answer / mithun

Ur answer is totally wrong.
Considering total no of males as x and total no of females
as y, we get first eqn as x+y=35000.
Now males are increased by 6% and females by 4%, so we get
2nd eqn as 1.06x+1.04y=36700.
Using simultaneous eqn, we get
No of males=15000
No of females=20000

Answer / ram

M = 15000 and F = 20000 is the value of current population
after 6% and 4% we will have M= 15900 and total F=20800
total is 36,700

Answer / sheetal

x + y = 35000 eq 1.
.06x + .04y = 1700 eq 2.
x= male
y= female

x = 35000-y .....put this eq in eq 2.

therefore,
y = 20,000 in the population of 35000
&
x = 15,000 in the population of 35000

therfore, population in 36,700 is
female 20,800 (4% 0f 20,000 = 800)
male 15,900 (6% of 15,000 = 900)

Answer / sam

its like 35000*50/100 = M=17500 F=17500
And then there is raise of 1700 in it
Male =1700*60/100=1020
male = 17500+1020 = 18520
Female= 1700*40/100 =680
Female= 17500+680 = 18180

Male = 18520
Female = 18180

Answer / rajeev ,cet bikaner 2nd yr

my answer is initialy population of male=15000&female=20000 and curent population is female=20800 & male=15900

Answer / harish sharavan

at the beginning the population can be denoted as x+y=3500
After 1 year the population becomes x+(x*6/100)+y+(y*4/100)=36700
thus the 2nd equation is 1.06x+1.04y=36700 thus solving both equations we get x=15000,y=20000
Therefore the Final no. females =20800
&males is 15900

Answer / sushant

35,000 is the population increase in 6% means=2100
and increase in 4% means=1400
2100
+1400
-------
3500
35000+3500=38500

Answer / ranjith

hi frdz ,,
i am not sure for the answer
total peoples after one year is 36700
i took 60% of males
and 40% was females
k
so frds
my answer is 22020is males
14680 is females

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