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10.If 100 ! = 100 x 99 x 98 x … x 2 x 1, the maximum power
of 20 which will divide 100 ! is
1] 21 2] 22 3] 23 4] 24
Plz Explain
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Answer / revathi
(100*99*..*1)/20^n.
20=2*2*5
so find the no of 5's present in the range.
it is 24.
ans:24
| Is This Answer Correct ? | 39 Yes | 4 No |
Answer / vigneswari vennila sathesh suj
calculate the no of 5's..(highest factor of 20)
100 --> 2
95--> 1
90 --> 1
85 --> 1
80 --> 1
75 --> 3
70 --> 1
65 -->1
60 -->1
55 --> 1
50 --> 2
45 -->1
40 -->1
35-->1
30-->1
25-->2
20-->1
15-->1
10-->1
5-->1
totally 24 5's...
| Is This Answer Correct ? | 8 Yes | 1 No |
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