how to prepare 5normality of hcl
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Answer / satish
Assay of Conc. HCl is 35%
Density of Conc. HCl is 1.18
Molecular Weight of HCl is 36.46
Normality=35x1.18x10/36.46
=11.3
Then apply V1N1=V2N2
V1X11.3=1000X5
V1=442.5mL
442.5 mL Of Con HCl is taken in 1000ml of water for 5N HCl.
Is This Answer Correct ? | 107 Yes | 30 No |
Answer / gokul charan
For 1 normality of HCL we will take 85ml of con.HCl make
up to 1000 ml with water.
Like that for 5 normality of HCL
5*85=425ml of con HCL make up to 1000 ml with water
Is This Answer Correct ? | 28 Yes | 24 No |
In HPLC Chromatographic separation Resolution equation is Rs = 1.18 (tR2 –tR1)/wh1+Wh2, Where, tR2 and tR1 is run time of eluent ratios of the distances from the point of application to the centers of the spots and the distance travelled by the solvent front from the point of application (retardation factor), and Wh1and Wh2 , is peak width of at half height. What is 1.18 ?
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