Answer / paresh jobanputtra, piramal

Hi Dear
If i want to make 70 ppm of Chloride solution from its Nacl salt
then i have to take 11.2 mg of Nacl salt in 100 ml of Solvent.
e.g Mol wt of Nacl # 58.5 gm per mole.
Na+cl#23+35.5.
it means 58.5 mg of Nacl salt in 1000ml of Solvent contains 35.5 ppm of Chloride.
but i want to make 70 ppm Chloride solution
so, 35.5 ppm----->58.5 mg Nacl salt
70 ppm-----> ?

=70*58.5/35.5(in 1000 ml of solvent)
=115.39 mg
so, 11.539 mg in 100 ml of solvent.

Regards,
Paresh Jobanputtra.

Answer / mahesh ashok bhiungade

If we want to 100 ppm of sodium solution from NaCl Salt.
Mol. Wt. Of NaCl is 58.5gm per mole
i.e Na+Cl =23+35.5
It means 1gm Na is present in 58.5/23=2.54g NaCl Salt
we know 1 ppm = mg/ 1000ml=0.001g/1000ml.
That means 1gm / 1000ml is 1000ppm
so 2.54gm NaCl (1gm Na)/1000ml = 1000ppm Na
But we Have 100ppm Na solution
2.54 g Nacl have 1000 ppm Na solution
That means 0.254gm NaCl have 100 ppm Na Solution.

Answer / gokulcharan

For Example we want to prepare 500ppm as follows
first we convert ppm to percentage.
500ppm=0.05%
Nacl M.Wt=58.5 cl=35.5

58.5*0.05/35.5 =0.0824g
weight 0.0824g of Nacl to prepare 500ppm.

Answer / malik

500 ppm = 500 mg/1 Liter Na .
let us prepare 2 liter so ,
500 * 2 = 1000 mg Na = 0.1 g Na.
wt of NaCl = Wt of Na (M.Wt of NaCl / M.Wt of Na)=
= 0.1 (58.5/23) = 0.25 g .

Answer / vivek

1gm/1000ml=1ppm
Therefore 1ppm Na solution is prepared as follows,
Mol. wt. of Nacl/Mol.wt.Na=58.5/23=2.54

when diss. 2.54gm Nacl in 1000ml water get 1ppm Na.

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