Answer / susie

Answer :

garbagevalue..1

Explanation:

p=&a[2][2][2] you declare only two 2D arrays. but you are
trying to access the third 2D(which you are not declared) it
will print garbage values. *q=***a starting address of a is
assigned integer pointer. now q is pointing to starting
address of a.if you print *q meAnswer:it will print first
element of 3D array.

main() { if ((1||0) && (0||1)) { printf("OK I am done."); } else { printf("OK I am gone."); } } a. OK I am done b. OK I am gone c. compile error d. none of the above

5 Answers   HCL,

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Write out a function that prints out all the permutations of a string. For example, abc would give you abc, acb, bac, bca, cab, cba. You can assume that all the characters will be unique.

5 Answers   IITR, Microsoft, Nike,

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main() { char p[ ]="%d\n"; p[1] = 'c'; printf(p,65); }

2 Answers  

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Program to find the largest sum of contiguous integers in the array. O(n)

11 Answers  

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main() { char str1[] = {‘s’,’o’,’m’,’e’}; char str2[] = {‘s’,’o’,’m’,’e’,’\0’}; while (strcmp(str1,str2)) printf(“Strings are not equal\n”); }

1 Answers  

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main() { float me = 1.1; double you = 1.1; if(me==you) printf("I love U"); else printf("I hate U"); }

1 Answers  

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void main() { int i=10, j=2; int *ip= &i, *jp = &j; int k = *ip/*jp; printf(“%d”,k); }

1 Answers  

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could you please send the program code for multiplying sparse matrix in c????

0 Answers  

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There were 10 records stored in “somefile.dat” but the following program printed 11 names. What went wrong? void main() { struct student { char name[30], rollno[6]; }stud; FILE *fp = fopen(“somefile.dat”,”r”); while(!feof(fp)) { fread(&stud, sizeof(stud), 1 , fp); puts(stud.name); } }

1 Answers  

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char *someFun() { char *temp = “string constant"; return temp; } int main() { puts(someFun()); }

1 Answers  

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Which one is taking more time and why ? :/home/amaresh/Testing# cat time.c //#include <stdio.h> #define EOF -1 int main() { register int c; while ((c = getchar()) != EOF) { putchar(c); } return 0; } ------------------- WIth stdio.h:- :/home/amaresh/Testing# time ./time_header hi hi hru? hru? real 0 m4.202s user 0 m0.000s sys 0 m0.004s ------------------ Witout stdio.h and with #define EOF -1 =================== /home/amaresh/Testing# time ./time_EOF hi hi hru? hru? real 0 m4.805s user 0 m0.004s sys 0 m0.004s -- From above two case , why 2nd case is taking more time ?

0 Answers  

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struct Foo { char *pName; }; main() { struct Foo *obj = malloc(sizeof(struct Foo)); clrscr(); strcpy(obj->pName,"Your Name"); printf("%s", obj->pName); } a. Your Name b. compile error c. Name d. Runtime error

3 Answers   HCL,

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