# include <stdio.h> int one_d[]={1,2,3}; main()

# include <stdio.h>

int one_d[]={1,2,3};

main()

{

int *ptr;

ptr=one_d;

ptr+=3;

printf("%d",*ptr);

}

Question Posted / susie

# include <stdio.h> int one_d[]={1,2,3}; main() { int *pt..

Answer / susie

Answer :

garbage value

Explanation:

ptr pointer is pointing to out of the array range of
one_d.

Is This Answer Correct ?

3 Yes

0 No

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