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Two cars travel in the same direction at 40km/hr at a
regular distance. A car comes in the opposite direction at
60km/hr. It meets each car in a gap of 8 seconds. What is
the distance between the two cars?
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Answer / rajesh kumar
Opposite coming car will cross in the speed of (40+60)km/hr
= 100kmhr
i.e = 100/3600km/second;
If it met 8 sec after first car crossed.
So (100/3600) x (8 sec) = 0.25km = 250 meter
| Is This Answer Correct ? | 5 Yes | 11 No |
Answer / richard
since the cars are coming in opposite direction
the car travelling in the opp dir move 134meters in 8 secs the other two move 89meters in 8 secs
since they move in opp dir
134-89=45
they are at a distance of 45 meters
| Is This Answer Correct ? | 2 Yes | 10 No |
Answer / ravi
car moving at 60Km/Hr moves 8 Kms in 8sec.
car moving at 40Km/Hr moves 5.33 Kms in 8sec.
so 8 KM +5.33 Km in 8 Secs
So total distance b/w cars 13.33 KM
| Is This Answer Correct ? | 13 Yes | 28 No |
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