Answer / indranil datta

The Car coming from opposite direction at 60KM/hr speed can
travel (60x8x1000)/3600=133.33 m in 8 secs
The car travelling at 40Km/hr speed can travel
(40*8*1000)/3600=88.88 m in 8 secs.
So the distance between 2 cars is (133.33+88.88)=222.21 m

Answer / satish kumar dhiman

opposit comminr car travel distance in 8 sec =134meter
two car travel distance in 8 sec =88meter

two car distance = 134+89 meter=223meter total

Answer / vadivelu

40 km/hr travels 88.88m in 8 secs
60 km/hr travels 133.33m in 8 secs
hence the distance 222.21 m

Answer / sanjay

speed = dist/time
two cars speed is 60+40=100km/hr(adding due to opposite direction)
should convert to m/s i.e 5/18
100*5/18=speed
time =8sec
by formula
dist= speed*time
100*5/18*8=223m
ans is 223

Answer / subash.s

222.23 metre

Answer / vadivelu

(40+60)/(5/18) * 8 = 222.5 m

Answer / imran

222.2

Answer / sas_mech

0.133 km

Answer / k10

speed = dist/time
two cars speed is 60+40=100km/hr(adding due to opposite direction)
should convert to m/s i.e 5/18
100*5/18=speed 
time =8sec
by formula
dist= speed*time
100*5/18*8=223m
ans is 223 

Answer / thangamurugan

They are asking only the distance of separation of the two
cars(40km/hr).
opposite car(60km/hr) meets 8sec interval.
so,we need to calculate how much distance the opposite car
travels in 8 sec.
i.e., distance= (60/3600)*8=0.13333km
=133.33m (ans)

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