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#include<stdio.h>
void main()
{
int i=1;
printf("%d%d%d",i++,++i,i);
}

Question Posted / medo

Answers were Sorted based on User's Feedback



#include<stdio.h> void main() { int i=1; printf("%d%d%d",i++,++i,i); }..

Answer / smriti

ans is 2 2 1.printf gets exe from rit to left so i =1,++i is 2,den i++ is 2 ..values are pushed into stack frm rit to left..so in stack 1 gets pushed first den 2 den 2.while pop d result is 2 2 1.

Is This Answer Correct ?    0 Yes 0 No

#include<stdio.h> void main() { int i=1; printf("%d%d%d",i++,++i,i); }..

Answer / vinod

3 2 1.because the print f function print right to leftand
the compiler reads left to right.thus answer is 3 2 1

Is This Answer Correct ?    0 Yes 0 No

#include<stdio.h> void main() { int i=1; printf("%d%d%d",i++,++i,i); }..

Answer / shruti

the answer will be:-
1,3,3
as i++ is postfix so first it will print the value then
increament..
after first increament the second preincreament comes and
the value becomes 3..
third time also it will 3..

Is This Answer Correct ?    4 Yes 5 No

#include<stdio.h> void main() { int i=1; printf("%d%d%d",i++,++i,i); }..

Answer / rakesh

getch();-missing

Is This Answer Correct ?    0 Yes 1 No

#include<stdio.h> void main() { int i=1; printf("%d%d%d",i++,++i,i); }..

Answer / kamal

211

Is This Answer Correct ?    0 Yes 2 No

#include<stdio.h> void main() { int i=1; printf("%d%d%d",i++,++i,i); }..

Answer / aaradhana

1,2,2

since to print the postincremented value then i takes the
value 1 then gets preincremented by1 & takes i=2.To print i
value then it takes the updated value i=2.

Is This Answer Correct ?    1 Yes 3 No

#include<stdio.h> void main() { int i=1; printf("%d%d%d",i++,++i,i); }..

Answer / kiran123456789

3 2 1

Is This Answer Correct ?    1 Yes 3 No

#include<stdio.h> void main() { int i=1; printf("%d%d%d",i++,++i,i); }..

Answer / ramya

Answer is 133.
first the compiler prints 'i' value and prints the value,
next it increments the 'i' value and then prints its value.

Is This Answer Correct ?    8 Yes 14 No

#include<stdio.h> void main() { int i=1; printf("%d%d%d",i++,++i,i); }..

Answer / priyadarshan kasta

1 2 2

becoz, this line will execute frm right to left side.
that is, first i=1, then ++i will be 2 and then i++ will be
printed as 2. So , it will print as 1 2 2(i.e i++,++i,i)

Is This Answer Correct ?    1 Yes 10 No

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