Is it possible to print a name without using commas, double quotes,semi-colons?
Answers were Sorted based on User's Feedback
Answer / vinay
void main()
{
char s[30]=
{72,69,76,76,79,33,32,84,72,73,83,32,73,83,32,86,73,78,65,89,32,83,65,76,76,65};
if(printf(s));
getch();
}
| Is This Answer Correct ? | 7 Yes | 2 No |
Answer / vinay salla
Explanation for above solution:
The answer is based on the ascii values..
We can take the ascii values of the characters together in
one char array..
| Is This Answer Correct ? | 3 Yes | 2 No |
Answer / pavan_mustyala
int main(int argc, char* argv[])
{
if(putchar('n') && putchar('a') && putchar('m') &&
putchar('e'))
{
}
return 0;
}
| Is This Answer Correct ? | 3 Yes | 2 No |
Answer / saravanan
#include<stdio.h>
#define fun(x) #x
int main()
{
if(printf(fun(INDIA))){}
}
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / srsabariselvan
void main()
{
if(printf("www.sslogic.blogspot.com"))
{
}
}
| Is This Answer Correct ? | 2 Yes | 6 No |
Answer / amit rathi
main ()
{
if (printf (hello))
return 0;
}
//printf returns number of characters printed so if
condition turns true.
same can be done with while,shitch,etc.
| Is This Answer Correct ? | 14 Yes | 23 No |
Is it possible to print a name without using commas, double quotes,semi-colons?
main() { show(); } void show() { printf("I'm the greatest"); }
int i=10; main() { extern int i; { int i=20; { const volatile unsigned i=30; printf("%d",i); } printf("%d",i); } printf("%d",i); }
main() { char a[4]="HELL"; printf("%s",a); }
void main() { int x,y=2,z; z=(z*=2)+(x=y=z); printf("%d",z); }
void main() { int i; char a[]="\0"; if(printf("%s\n",a)) printf("Ok here \n"); else printf("Forget it\n"); }
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