Answer / dan

if (x & (x-1)) // false only if x is a power of 2

Answer / vadivel

# include <stdio.h>

void main()
{
int n;
scanf("%d",&n);
if( n & (n-1) )
printf("Not a Power of 2");
else
printf("Power of 2");
}

Answer / ataraxic

Previous post -- It's wrong... absolutely...

Answer / phil

if (x && !(x & (x-1)) == 0)

Answer / jb

(x ^ x-1) == ((x << 1) - 1)

Answer / ashutosh

I think
if (x & (x-1)) wont work when number is negative.

Answer / natmat

(~i & (i-1)) == (i - 1))

Answer / fjords

if (int(log(x)) == log(x)) // log is to the base 2

Answer / rahul priyadarshi

#define ISPOW2(x) ((x==1)?1:(x&(x-1)))?0:1

Answer / yevgen

if ((num XOR (num - 1)) == num + num - 1) return true;
else return false;

main() { char *a = "Hello "; char *b = "World"; clrscr(); printf("%s", strcpy(a,b)); } a. “Hello” b. “Hello World” c. “HelloWorld” d. None of the above

4 Answers   Corporate Society, HCL,

why array index always strats wuth zero?

2 Answers  

You are given any character string. Find the number of sets of vowels that come in the order of aeiou in the given string. For eg., let the given string be DIPLOMATIC. The answer returned must be "The number of sets is 2" and "The sets are "IO and AI". Vowels that form a singleton set must be neglected. Try to post the program executable in gcc or g++ or in java.

3 Answers  

write a c-program to display the time using FOR loop

3 Answers   HCL,

What is wrong with the following code? int *foo() { int *s = malloc(sizeof(int)100); assert(s != NULL); return s; }

1 Answers  

Is it possible to type a name in command line without ant quotes?

1 Answers   Excel, Infosys,

main() { char name[10],s[12]; scanf(" \"%[^\"]\"",s); } How scanf will execute?

2 Answers  

write a c-program to find gcd using recursive functions

5 Answers   HTC, Infotech,

main() { char *p; p="%d\n"; p++; p++; printf(p-2,300); }

1 Answers  

#include<stdio.h> main() { const int i=4; float j; j = ++i; printf("%d %f", i,++j); }

1 Answers  

how to swap 3 nos without using temporary variable

4 Answers   Satyam,

main() { char s[ ]="man"; int i; for(i=0;s[ i ];i++) printf("\n%c%c%c%c",s[ i ],*(s+i),*(i+s),i[s]); }

1 Answers   DCE,