Answer / susie

Answer :

1

Explanation

The three usages of name errors can be distinguishable
by the compiler at any instance, so valid (they are in
different namespaces).

Typedef struct error{int warning, error, exception;}error;

This error can be used only by preceding the error by struct
kayword as in:

struct error someError;

typedef struct error{int warning, error, exception;}error;

This can be used only after . (dot) or -> (arrow) operator
preceded by the variable name as in :

g1.error =1;

printf("%d",g1.error);

typedef struct error{int warning, error, exception;}error;

This can be used to define variables without using the
preceding struct keyword as in:

error g1;

Since the compiler can perfectly distinguish between these
three usages, it is perfectly legal and valid.

Note

This code is given here to just explain the concept
behind. In real programming don’t use such overloading of
names. It reduces the readability of the code. Possible
doesn’t mean that we should use it!

void main() { int i=10, j=2; int *ip= &i, *jp = &j; int k = *ip/*jp; printf(“%d”,k); }

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Link list in reverse order.

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Cau u say the output....?

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typedef struct error{int warning, error, exception;}error; main() { error g1; g1.error =1; printf("%d",g1.error); }

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struct aaa{ struct aaa *prev; int i; struct aaa *next; }; main() { struct aaa abc,def,ghi,jkl; int x=100; abc.i=0;abc.prev=&jkl; abc.next=&def; def.i=1;def.prev=&abc;def.next=&ghi; ghi.i=2;ghi.prev=&def; ghi.next=&jkl; jkl.i=3;jkl.prev=&ghi;jkl.next=&abc; x=abc.next->next->prev->next->i; printf("%d",x); }

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Question: We would like to design and implement a programming solution to the reader-writer problem using semaphores in C language under UNIX. We assume that we have three readers and two writers processes that would run concurrently. A writer is to update (write) into one memory location (let’s say a variable of type integer named temp initialized to 0). In the other hand, a reader is to read the content of temp and display its content on the screen in a formatted output. One writer can access the shared data exclusively without the presence of other writer or any reader, whereas, a reader may access the shared memory for reading with the presence of other readers (but not writers).

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Is the following code legal? typedef struct a { int x; aType *b; }aType

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