What is the subtle error in the following code segment?
void fun(int n, int arr[])
{
int *p=0;
int i=0;
while(i++<n)
p = &arr[i];
*p = 0;
}
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Answer Posted / susie
Answer : & Explanation:
If the body of the loop never executes p is assigned no
address. So p remains NULL where *p =0 may result in problem
(may rise to runtime error “NULL pointer assignment” and
terminate the program).
| Is This Answer Correct ? | 1 Yes | 0 No |
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