Answer / susie

Answer :

0

Explanation:

! is a logical operator. In C the value 0 is considered to
be the boolean value FALSE, and any non-zero value is
considered to be the boolean value TRUE. Here 2 is a
non-zero value so TRUE. !TRUE is FALSE (0) so it prints 0.

Given a list of numbers ( fixed list) Now given any other list, how can you efficiently find out if there is any element in the second list that is an element of the first list (fixed list)

3 Answers   Disney, Google, ZS Associates,

---

How to palindrom string in c language?

6 Answers   Google,

---

int i=10; main() { extern int i; { int i=20; { const volatile unsigned i=30; printf("%d",i); } printf("%d",i); } printf("%d",i); }

1 Answers  

---

What are the files which are automatically opened when a C file is executed?

1 Answers  

---

You are given any character string. Find the number of sets of vowels that come in the order of aeiou in the given string. For eg., let the given string be DIPLOMATIC. The answer returned must be "The number of sets is 2" and "The sets are "IO and AI". Vowels that form a singleton set must be neglected. Try to post the program executable in gcc or g++ or in java.

3 Answers  

---

# include<stdio.h> aaa() { printf("hi"); } bbb(){ printf("hello"); } ccc(){ printf("bye"); } main() { int (*ptr[3])(); ptr[0]=aaa; ptr[1]=bbb; ptr[2]=ccc; ptr[2](); }

1 Answers  

---

Code for 1>"ascii to string" 2>"string to ascii"

1 Answers   Aricent, Global Logic,

---

#include<stdio.h> main() { FILE *ptr; char i; ptr=fopen("zzz.c","r"); while((i=fgetch(ptr))!=EOF) printf("%c",i); }

1 Answers  

---

main() { int y; scanf("%d",&y); // input given is 2000 if( (y%4==0 && y%100 != 0) || y%100 == 0 ) printf("%d is a leap year"); else printf("%d is not a leap year"); }

1 Answers  

---

void main() { int const * p=5; printf("%d",++(*p)); }

3 Answers   Infosys, Made Easy, State Bank Of India SBI,

---

In the following pgm add a stmt in the function fun such that the address of 'a' gets stored in 'j'. main(){ int * j; void fun(int **); fun(&j); } void fun(int **k) { int a =0; /* add a stmt here*/ }

1 Answers  

---

main() { int i=-1; -i; printf("i = %d, -i = %d \n",i,-i); }

1 Answers  

---