main()
{
int i=0;
for(;i++;printf("%d",i)) ;
printf("%d",i);
}
Answer / susie
Answer :
1
Explanation:
before entering into the for loop the checking condition is
"evaluated". Here it evaluates to 0 (false) and comes out of
the loop, and i is incremented (note the semicolon after the
for loop).
Is This Answer Correct ? | 25 Yes | 9 No |
¦void main() ¦{ ¦int i=10,j; ¦ j=i+++i+++i; ¦printf("%d",j); ¦getch(); ¦} ¦ output:-30 but in same question if we write as- ¦void main() ¦{ ¦int i=10; ¦ int j=i+++i+++i; ¦printf("%d",j); ¦getch(); ¦} ¦ output:-33 why output is changed from 30 to 33. Can any body answer...
Cau u say the output....?
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