Answer / susie

Answer :

Compiler error (in the line arr1 list = {0,1,2,3,4})

Explanation:

arr2 is declared of type array of size 5 of characters. So
it can be used to declare the variable name of the type
arr2. But it is not the case of arr1. Hence an error.

Rule of Thumb:

#defines are used for textual replacement whereas typedefs
are used for declaring new types.

void main() { int i=5; printf("%d",i+++++i); }

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why java is platform independent?

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What is the output for the program given below typedef enum errorType{warning, error, exception,}error; main() { error g1; g1=1; printf("%d",g1); }

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main() { char *p = “ayqm”; printf(“%c”,++*(p++)); }

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Write a C program to print ‘Campus Force training’ without using even a single semicolon in the program.

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main() { printf("%d", out); } int out=100;

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Which one is taking more time and why ? :/home/amaresh/Testing# cat time.c //#include <stdio.h> #define EOF -1 int main() { register int c; while ((c = getchar()) != EOF) { putchar(c); } return 0; } ------------------- WIth stdio.h:- :/home/amaresh/Testing# time ./time_header hi hi hru? hru? real 0 m4.202s user 0 m0.000s sys 0 m0.004s ------------------ Witout stdio.h and with #define EOF -1 =================== /home/amaresh/Testing# time ./time_EOF hi hi hru? hru? real 0 m4.805s user 0 m0.004s sys 0 m0.004s -- From above two case , why 2nd case is taking more time ?

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Write a routine to implement the polymarker function

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How we print the table of 2 using for loop in c programing?

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void main() { printf(“sizeof (void *) = %d \n“, sizeof( void *)); printf(“sizeof (int *) = %d \n”, sizeof(int *)); printf(“sizeof (double *) = %d \n”, sizeof(double *)); printf(“sizeof(struct unknown *) = %d \n”, sizeof(struct unknown *)); }

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main() { int k=1; printf("%d==1 is ""%s",k,k==1?"TRUE":"FALSE"); }

1 Answers  

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write the function. if all the character in string B appear in string A, return true, otherwise return false.

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