main() { int x=5; clrscr(); for(;x==0;x--) { printf(&qu

main()

{

int x=5;

clrscr();

for(;x==0;x--) {

printf("x=%d\n”", x--);

}

}

a. 4, 3, 2, 1, 0

b. 1, 2, 3, 4, 5

c. 0, 1, 2, 3, 4

d. none of the above

Question Posted / guest

3 Answers
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main() { int x=5; clrscr(); for(;x==0;x--) { printf("x=%d\n”", ..

Answer / guest

d) prints nothing, as condition x==0 is False

Is This Answer Correct ?

11 Yes

0 No

main() { int x=5; clrscr(); for(;x==0;x--) { printf("x=%d\n”", ..

Answer / ana

nothing

Is This Answer Correct ?

4 Yes

0 No

main() { int x=5; clrscr(); for(;x==0;x--) { printf("x=%d\n”", ..

Answer / ranjith v

d:None of the above
Explanation:
In for loop the condition x==0,i.e;x0 is assigned to
zero.which means x value will be 0 not the 5.so it causes error.

Is This Answer Correct ?

1 Yes

0 No

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