Answer / susie

Answer :

100

Explanation:

Preprocessor executes as a seperate pass before
the execution of the compiler. So textual replacement of
clrscr() to 100 occurs.The input program to compiler looks
like this :

main()

{

100;

printf("%d\n",100);

}

Note:

100; is an executable statement but with no
action. So it doesn't give any problem

Answer / naveen

yes it works and prints 100 because we defined clrscr() to
100. we can also set values to any predefined functions

int swap(int *a,int *b) { *a=*a+*b;*b=*a-*b;*a=*a-*b; } main() { int x=10,y=20; swap(&x,&y); printf("x= %d y = %d\n",x,y); }

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