Answer / susie

Answer :

100

Explanation:

Preprocessor executes as a seperate pass before
the execution of the compiler. So textual replacement of
clrscr() to 100 occurs.The input program to compiler looks
like this :

main()

{

100;

printf("%d\n",100);

}

Note:

100; is an executable statement but with no
action. So it doesn't give any problem

Answer / naveen

yes it works and prints 100 because we defined clrscr() to
100. we can also set values to any predefined functions

main ( ) { static char *s[ ] = {“black”, “white”, “yellow”, “violet”}; char **ptr[ ] = {s+3, s+2, s+1, s}, ***p; p = ptr; **++p; printf(“%s”,*--*++p + 3); }

1 Answers  

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main() { int x=5; clrscr(); for(;x==0;x--) { printf("x=%d\n”", x--); } } a. 4, 3, 2, 1, 0 b. 1, 2, 3, 4, 5 c. 0, 1, 2, 3, 4 d. none of the above

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main() { int k=1; printf("%d==1 is ""%s",k,k==1?"TRUE":"FALSE"); }

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