Answer / susie

Answer :

100

Explanation:

Preprocessor executes as a seperate pass before
the execution of the compiler. So textual replacement of
clrscr() to 100 occurs.The input program to compiler looks
like this :

main()

{

100;

printf("%d\n",100);

}

Note:

100; is an executable statement but with no
action. So it doesn't give any problem

Answer / naveen

yes it works and prints 100 because we defined clrscr() to
100. we can also set values to any predefined functions

main() { int c[ ]={2.8,3.4,4,6.7,5}; int j,*p=c,*q=c; for(j=0;j<5;j++) { printf(" %d ",*c); ++q; } for(j=0;j<5;j++){ printf(" %d ",*p); ++p; } }

2 Answers   CSS, Wipro,

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Given only putchar (no sprintf, itoa, etc.) write a routine putlong that prints out an unsigned long in decimal.

6 Answers   Fusion Systems GmbH,

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struct Foo { char *pName; char *pAddress; }; main() { struct Foo *obj = malloc(sizeof(struct Foo)); clrscr(); obj->pName = malloc(100); obj->pAddress = malloc(100); strcpy(obj->pName,"Your Name"); strcpy(obj->pAddress, "Your Address"); free(obj); printf("%s", obj->pName); printf("%s", obj->pAddress); } a. Your Name, Your Address b. Your Address, Your Address c. Your Name Your Name d. None of the above

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How to return multiple values from a function?

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¦void main() ¦{ ¦int i=10,j; ¦ j=i+++i+++i; ¦printf("%d",j); ¦getch(); ¦} ¦ output:-30 but in same question if we write as- ¦void main() ¦{ ¦int i=10; ¦ int j=i+++i+++i; ¦printf("%d",j); ¦getch(); ¦} ¦ output:-33 why output is changed from 30 to 33. Can any body answer...

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write a program to Insert in a sorted list

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#include <stdio.h> main() { char * str = "hello"; char * ptr = str; char least = 127; while (*ptr++) least = (*ptr<least ) ?*ptr :least; printf("%d",least); }

1 Answers  

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main() { char a[4]="HELLO"; printf("%s",a); }

3 Answers   CSC,

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main() { int a=2,*f1,*f2; f1=f2=&a; *f2+=*f2+=a+=2.5; printf("\n%d %d %d",a,*f1,*f2); }

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how to return a multiple value from a function?

2 Answers   Wipro,

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typedef struct error{int warning, error, exception;}error; main() { error g1; g1.error =1; printf("%d",g1.error); }

1 Answers  

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