Answer / susie

Answer :

c=2;

Explanation:

Here unary minus (or negation) operator is used
twice. Same maths rules applies, ie. minus * minus= plus.

Note:

However you cannot give like --2. Because --
operator can only be applied to variables as a decrement
operator (eg., i--). 2 is a constant and not a variable.

Write a Program that Inputs 10 Numbers in an Array and Show the Maximum Number

2 Answers   Ace Info,

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In a gymnastic competition, scoring is based on the average of all scores given by the judges excluding the maximum and minimum scores. Let the user input the number of judges, after that, input the scores from the judges. Output the average score. Note: In case, more than two judges give the same score and it happens that score is the maximum or minimum then just eliminate two scores. For example, if the number of judges is 5 and all of them give 10 points each. Then the maximum and minimum score is 10. So the computation would be 10+10+10, this time. The output should be 10 because 30/3 is 10.

0 Answers   TCS,

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main( ) { static int a[ ] = {0,1,2,3,4}; int *p[ ] = {a,a+1,a+2,a+3,a+4}; int **ptr = p; ptr++; printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr); *ptr++; printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr); *++ptr; printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr); ++*ptr; printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr); }

2 Answers   Persistent,

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main() { int i =10, j = 20; clrscr(); printf("%d, %d, ", j-- , --i); printf("%d, %d ", j++ , ++i); } a. 20, 10, 20, 10 b. 20, 9, 20, 10 c. 20, 9, 19, 10 d. 19, 9, 20, 10

4 Answers   HCL,

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How to palindrom string in c language?

6 Answers   Google,

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Print an integer using only putchar. Try doing it without using extra storage.

2 Answers  

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main() { signed int bit=512, i=5; for(;i;i--) { printf("%d\n", bit = (bit >> (i - (i -1)))); } } a. 512, 256, 128, 64, 32 b. 256, 128, 64, 32, 16 c. 128, 64, 32, 16, 8 d. 64, 32, 16, 8, 4

2 Answers   HCL,

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main() { float f=5,g=10; enum{i=10,j=20,k=50}; printf("%d\n",++k); printf("%f\n",f<<2); printf("%lf\n",f%g); printf("%lf\n",fmod(f,g)); }

1 Answers  

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main(){ char a[100]; a[0]='a';a[1]]='b';a[2]='c';a[4]='d'; abc(a); } abc(char a[]){ a++; printf("%c",*a); a++; printf("%c",*a); }

2 Answers  

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#define f(g,g2) g##g2 main() { int var12=100; printf("%d",f(var,12)); }

3 Answers  

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Printf can be implemented by using __________ list.

3 Answers  

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main() { void swap(); int x=10,y=8; swap(&x,&y); printf("x=%d y=%d",x,y); } void swap(int *a, int *b) { *a ^= *b, *b ^= *a, *a ^= *b; }

2 Answers  

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