Answer / susie

Answer :

c=2;

Explanation:

Here unary minus (or negation) operator is used
twice. Same maths rules applies, ie. minus * minus= plus.

Note:

However you cannot give like --2. Because --
operator can only be applied to variables as a decrement
operator (eg., i--). 2 is a constant and not a variable.

main() { char i=0; for(;i>=0;i++) ; printf("%d\n",i); }

2 Answers  

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Write a complete program that consists of a function that can receive two numbers from a user (M and N) as a parameter. Then print all the numbers between the two numbers including the number itself. If the value of M is smaller than N, print the numbers in ascending flow. If the value of M is bigger than N, print the numbers in descending flow. may i know how the coding look like?

2 Answers  

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# include<stdio.h> aaa() { printf("hi"); } bbb(){ printf("hello"); } ccc(){ printf("bye"); } main() { int (*ptr[3])(); ptr[0]=aaa; ptr[1]=bbb; ptr[2]=ccc; ptr[2](); }

1 Answers  

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plz send me all data structure related programs

2 Answers  

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main() { int i=10; i=!i>14; Printf ("i=%d",i); }

1 Answers  

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int main() { int x=10; printf("x=%d, count of earlier print=%d", x,printf("x=%d, y=%d",x,--x)); getch(); } ================================================== returns error>> ld returned 1 exit status =================================================== Does it have something to do with printf() inside another printf().

1 Answers  

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3) Int Matrix of certain size was given, We had few valu= es in it like this. =97=97=97=97=97=97=97=97=97=97=97 1 = | 4 | | 5 | &= nbsp; | 45 =97=97=97=97=97=97=97=97=97=97=97 &n= bsp; | 3 | 3 | 5 | = | 4 =97=97=97=97=97=97=97=97=97=97=97 34 |&nbs= p; 3 | 3 | | 12 | &= nbsp; =97=97=97=97=97=97=97=97=97=97=97 3 | &nbs= p; | 3 | 4 | = | 3 =97=97=97=97=97=97=97=97=97=97=97 3 | = ; | | | = ; 3 | =97=97=97=97=97=97=97=97=97=97=97 &= nbsp; | | 4 | = ; | 4 | 3 We w= ere supposed to move back all the spaces in it at the end. Note: = If implemented this prog using recursion, would get higher preference.

0 Answers   RoboSoft,

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main(){ int a= 0;int b = 20;char x =1;char y =10; if(a,b,x,y) printf("hello"); }

1 Answers   TCS,

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Write a program to receive an integer and find its octal equivalent?

7 Answers  

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#include<stdio.h> main() { struct xx { int x; struct yy { char s; struct xx *p; }; struct yy *q; }; }

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Which one is taking more time and why ? :/home/amaresh/Testing# cat time.c //#include <stdio.h> #define EOF -1 int main() { register int c; while ((c = getchar()) != EOF) { putchar(c); } return 0; } ------------------- WIth stdio.h:- :/home/amaresh/Testing# time ./time_header hi hi hru? hru? real 0 m4.202s user 0 m0.000s sys 0 m0.004s ------------------ Witout stdio.h and with #define EOF -1 =================== /home/amaresh/Testing# time ./time_EOF hi hi hru? hru? real 0 m4.805s user 0 m0.004s sys 0 m0.004s -- From above two case , why 2nd case is taking more time ?

0 Answers  

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main() { signed int bit=512, i=5; for(;i;i--) { printf("%d\n", bit >> (i - (i -1))); } } a. 512, 256, 0, 0, 0 b. 256, 256, 0, 0, 0 c. 512, 512, 512, 512, 512 d. 256, 256, 256, 256, 256

2 Answers   HCL,

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