Answer / vadivel_152

#include<stdio.h>
#include<string.h>

int vowelsubset();
void separate();

char vowel[] = {'a','e','i','o','u'};
char str[100],res[50];
int main()
{
scanf("%s",str);
separate();
printf("The No. of sets are: %d\n",vowelsubset());
return 0;
}
void separate()
{
int i,j,x=0;
for(i = 0;i<strlen(str);i++)
for(j = 0;j<5;j++)
if(str[i] == vowel[j])
res[x++] = str[i];
res[x] = ''\0;
}
int vowelsubset()
{
if( (strlen(res)==0 )|| (strlen(res)==1) )
return 0;
int cnt = 0,i,j,x,k,flag;
for(i = 0;i<strlen(res);i++)
{
for(j = 0;j<5;j++)
if( (res[i] == vowel[j]) && (vowel[j]!='u'))
{
flag = 0;
for(k = i+1;k<strlen(res);k++)
{
if(res[k]<=vowel[j])
{
i = k-1;
goto label;
}
for(x = j+1;x<5;x++)
if(res[k] == vowel[x])
flag = 1;

}
label:
if(flag == 1)
cnt++;
}
}
return cnt;
}

Answer / sumedha sk

str="DIPLOMATIC"
str=lcase(str)
strlen=len(str)

vowelcnt=0

For pos=1 to strlen
charofstr=mid(str,pos,1)
If (charofstr="a") or (charofstr="e") or
(charofstr="i") or
(charofstr="o") or (charofstr="u") Then
vowelcnt=vowelcnt+1
End If
Next

msgbox "no of vowels are:"& vowelcnt

Answer / rohini

str="DIPLOMATIC"
str=lcase(str)
strlen=len(str)

vowelcnt=0

For pos=1 to strlen
charofstr=mid(str,pos,1)
If (charofstr="a") or (charofstr="e") or (charofstr="i") or
(charofstr="o") or (charofstr="u") Then
vowelcnt=vowelcnt+1
End If
Next

msgbox "no of vowels are:"& vowelcnt

main() { char a[4]="HELL"; printf("%s",a); }

3 Answers   Wipro,

---

main() { signed int bit=512, i=5; for(;i;i--) { printf("%d\n", bit >> (i - (i -1))); } } a. 512, 256, 0, 0, 0 b. 256, 256, 0, 0, 0 c. 512, 512, 512, 512, 512 d. 256, 256, 256, 256, 256

2 Answers   HCL,

---

why is printf("%d %d %d",i++,--i,i--);

4 Answers   Apple, Cynity, TCS,

---

how can i cast a char type array to an int type array

2 Answers  

---

main() { int i = 257; int *iPtr = &i; printf("%d %d", *((char*)iPtr), *((char*)iPtr+1) ); }

1 Answers   CSC,

---

---

Is the following code legal? typedef struct a aType; struct a { int x; aType *b; };

1 Answers  

---

abcdedcba abc cba ab ba a a

2 Answers  

---

#include<stdio.h> main() { int a[2][2][2] = { {10,2,3,4}, {5,6,7,8} }; int *p,*q; p=&a[2][2][2]; *q=***a; printf("%d----%d",*p,*q); }

1 Answers  

---

prog. to produce 1 2 3 4 5 6 7 8 9 10

4 Answers   TCS,

---

main() { int c[ ]={2.8,3.4,4,6.7,5}; int j,*p=c,*q=c; for(j=0;j<5;j++) { printf(" %d ",*c); ++q; } for(j=0;j<5;j++){ printf(" %d ",*p); ++p; } }

1 Answers  

---

#include"math.h" void main() { printf("Hi everybody"); } if <stdio.h> will be included then this program will must compile, but as we know that when we include a header file in "" then any system defined function find its defination from all the directrives. So is this code of segment will compile? If no then why?

2 Answers  

---

#include<stdio.h> main() { char s[]={'a','b','c','\n','c','\0'}; char *p,*str,*str1; p=&s[3]; str=p; str1=s; printf("%d",++*p + ++*str1-32); }

2 Answers   CNSI,

---