Answer / vadivel_152

#include<stdio.h>
#include<string.h>

int vowelsubset();
void separate();

char vowel[] = {'a','e','i','o','u'};
char str[100],res[50];
int main()
{
scanf("%s",str);
separate();
printf("The No. of sets are: %d\n",vowelsubset());
return 0;
}
void separate()
{
int i,j,x=0;
for(i = 0;i<strlen(str);i++)
for(j = 0;j<5;j++)
if(str[i] == vowel[j])
res[x++] = str[i];
res[x] = ''\0;
}
int vowelsubset()
{
if( (strlen(res)==0 )|| (strlen(res)==1) )
return 0;
int cnt = 0,i,j,x,k,flag;
for(i = 0;i<strlen(res);i++)
{
for(j = 0;j<5;j++)
if( (res[i] == vowel[j]) && (vowel[j]!='u'))
{
flag = 0;
for(k = i+1;k<strlen(res);k++)
{
if(res[k]<=vowel[j])
{
i = k-1;
goto label;
}
for(x = j+1;x<5;x++)
if(res[k] == vowel[x])
flag = 1;

}
label:
if(flag == 1)
cnt++;
}
}
return cnt;
}

Answer / sumedha sk

str="DIPLOMATIC"
str=lcase(str)
strlen=len(str)

vowelcnt=0

For pos=1 to strlen
charofstr=mid(str,pos,1)
If (charofstr="a") or (charofstr="e") or
(charofstr="i") or
(charofstr="o") or (charofstr="u") Then
vowelcnt=vowelcnt+1
End If
Next

msgbox "no of vowels are:"& vowelcnt

Answer / rohini

str="DIPLOMATIC"
str=lcase(str)
strlen=len(str)

vowelcnt=0

For pos=1 to strlen
charofstr=mid(str,pos,1)
If (charofstr="a") or (charofstr="e") or (charofstr="i") or
(charofstr="o") or (charofstr="u") Then
vowelcnt=vowelcnt+1
End If
Next

msgbox "no of vowels are:"& vowelcnt

union u { union u { int i; int j; }a[10]; int b[10]; }u; main() { printf("\n%d", sizeof(u)); printf(" %d", sizeof(u.a)); // printf("%d", sizeof(u.a[4].i)); } a. 4, 4, 4 b. 40, 4, 4 c. 1, 100, 1 d. 40 400 4

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