Answer / susie

Answer :

2 2 2 2 2 2 3 4 6 5

Explanation:

Initially pointer c is assigned to both p and q.
In the first loop, since only q is incremented and not c ,
the value 2 will be printed 5 times. In second loop p itself
is incremented. So the values 2 3 4 6 5 will be printed.

main( ) { char *q; int j; for (j=0; j<3; j++) scanf(“%s” ,(q+j)); for (j=0; j<3; j++) printf(“%c” ,*(q+j)); for (j=0; j<3; j++) printf(“%s” ,(q+j)); }

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