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main()
{
int c[ ]={2.8,3.4,4,6.7,5};
int j,*p=c,*q=c;
for(j=0;j<5;j++) {
printf(" %d ",*c);
++q; }
for(j=0;j<5;j++){
printf(" %d ",*p);
++p; }
}
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Answer / susie
Answer :
2 2 2 2 2 2 3 4 6 5
Explanation:
Initially pointer c is assigned to both p and q.
In the first loop, since only q is incremented and not c ,
the value 2 will be printed 5 times. In second loop p itself
is incremented. So the values 2 3 4 6 5 will be printed.
| Is This Answer Correct ? | 46 Yes | 9 No |
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C Code 
