Answer / odelu vanga

*f2=*f2+(*f=*f2+(a=a+2.5))

a=a+2.5=4
so *f2=4
*f2=*f2+4=8
now *f2=8
so *f2=*f2+8=16

ans:- 16 16 16

Answer / susie

Answer :

16 16 16

Explanation:

f1 and f2 both refer to the same memory location a. So
changes through f1 and f2 ultimately affects only the value
of a.

Answer / kamlesh meghwal

LOL@Govind Verma....how u r gettin 888..hehe..!!1

Answer / forgot_my_name

Since we are modifying same variable three times in the same line (before sequence point ) so we broke the rules, so whatever compiler says would be right..
@Kamlesh Meghwal : In GCC compiler ans is 8 8 8.

Answer / vamshikrishna

12 12 12

explanition.
printf takes the last updated value and prints for every var
i.e,

a=a+2.5=4
so f2=4
f2=f2+4=8
here again f2 =4 "since f2=&a"
so f2=f2+4=12

Answer / govind verma

but ans is 888 but i dnt know how....

main() { int x=5; clrscr(); for(;x<= 0;x--) { printf("x=%d ", x--); } } a. 5, 3, 1 b. 5, 2, 1, c. 5, 3, 1, -1, 3 d. –3, -1, 1, 3, 5

2 Answers   HCL,

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1 Answers   Wipro,

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1 Answers   HCL,

void main() { int i=5; printf("%d",i++ + ++i); }

3 Answers  

how to programme using switch statements and fuctions, a programme that will output two even numbers, two odd numbers and two prime numbers of the users chioce.

0 Answers   Mbarara University of Science and Technology,

how to return a multiple value from a function?

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3 Answers  

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13 Answers   Adobe, Amazon, EFI, Imagination Technologies,

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3 Answers  

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1 Answers