Answer / abishekmittal

Answer 1. is correct. In addition to it, with the decrease
of voltage, current will also come down (V is directly
proportional to I for constant R). Hence the bulb will get
dimmed as the I^2R also gets reduced

Answer / suresh

IF THE BULB POWER HAVINE 60W MEANS ,I^2R IS 60W.IF VOLTAGE
DECREASED BELOW RATED VALUE .BULB WILL DIM.

Answer / victor

answers #1&2 are applicable only in purely resistive load,
ex. an incandescent bulb , so both were correct .

Answer / md. obaydur rahman

All the above answers are wrong because we know that for a
constant power rating,
P=V*I
i,e. I=P/V
From the above equation we can see that if the voltage
changes the current is also changed for a constant power
rating i,e. if voltage reduced the device draws more current
to consume its power rating and vice versa.

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