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salary of a person increases every year by 20%. his salary
in the year 2001 was Rs. 26,640. what was salary in 1999?
well i am confused. suggest how to do such probs in steps.
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Answer / shyam
let the salary in 1999 was x.
In 2000 the salary will be 6x/5.
in 2001 the salary will be [6x/5]+[6x/5][1/5]=36x/25
now 36x/25=26,640
x= 18500
| Is This Answer Correct ? | 50 Yes | 5 No |
Answer / kk
Let his salary be x in the year 1999.
In 2000, x + (20/100)x
i.e. = 1.2x,
in 2001, 1.2x + (20/100)1.2x , i.e = 1.44x,
but we already know salary of year 2001 is 26640,
hence, 1.44x = 26640, therefore x = 18500.
hence solved.
| Is This Answer Correct ? | 42 Yes | 3 No |
Answer / mohit
let the salary in 1999 is x then assume the %increase as
compound interest.
x(1+20/100)^2=26640
x=Rs. 18,500
| Is This Answer Correct ? | 12 Yes | 1 No |
Answer / vignesh1988i
rs.17049 in 1999.....
it is said that every year it is 20% increase.... if we are in 2001... the salary at the yr. 2000 will be 20% less of the salary... using the same concept the problem moves.........
thank u
| Is This Answer Correct ? | 5 Yes | 16 No |
Answer / nisar
2001 salary is 26,640 then 20% of this is 5328
26,640
-5,328
=21,328 which is his salary in 2000
so 20 % of 21328 is 4262.4
then 21,312
-4,262.4
is 17,049.6 which is his salary of year 1999
| Is This Answer Correct ? | 7 Yes | 24 No |
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