Answer / shyam

let the salary in 1999 was x.
In 2000 the salary will be 6x/5.
in 2001 the salary will be [6x/5]+[6x/5][1/5]=36x/25
now 36x/25=26,640
x= 18500

Answer / kk

Let his salary be x in the year 1999.

In 2000, x + (20/100)x
i.e. = 1.2x,
in 2001, 1.2x + (20/100)1.2x , i.e = 1.44x,

but we already know salary of year 2001 is 26640,
hence, 1.44x = 26640, therefore x = 18500.
hence solved.

Answer / pavan

26,640*(5/6)*(5/6)
=18,500

Answer / mohit

let the salary in 1999 is x then assume the %increase as
compound interest.

x(1+20/100)^2=26640
x=Rs. 18,500

Answer / yogesh poul

18500

Answer / vignesh1988i

rs.17049 in 1999.....

it is said that every year it is 20% increase.... if we are in 2001... the salary at the yr. 2000 will be 20% less of the salary... using the same concept the problem moves.........




thank u

Answer / guest

17049.6

Answer / yogesh poul

17849.6rs

Answer / sudha

Rs. 17849.6

Answer / nisar

2001 salary is 26,640 then 20% of this is 5328

26,640
-5,328
=21,328 which is his salary in 2000

so 20 % of 21328 is 4262.4

then 21,312
-4,262.4
is 17,049.6 which is his salary of year 1999

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