A tank can be filled by pipe A in 30 minutes and by pipe B
in 24 minutes. Outlet pipe C can empty the full tank in one
hour and twenty minutes.
If the tank is empty initially and if all the three pipes A,
B and C are opened simultaneously, in how much time will the
tank be full?
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Answer / guest
The tank will be full in 16 minutes.
In one minute,
pipe A can fill 1/30 part of the tank.
pipe B can fill 1/24 part of the tank.
pipe C can empty 1/80 part of the tank.
Thus, the net water level in one minute is
= 1/30 + 1/24 - 1/80
= 15/240 part of the tank
Hence, the tank will be full in 240/15 i.e. 16 minutes.
| Is This Answer Correct ? | 29 Yes | 5 No |
Answer / mithilesh.patidar
obviasly 16 minutes.............b'cas
in 1 minute a can fill the tank=1/30
in 1 minute b can fill the tank=1/24
then both fill the tank in 1 minute=1/30+1/24
=54/30*24
=3/40
c can empty the tank in 1 minute=1/80
then pipe will fill in=3/40-1/80
=1/16
hence
for fill the full tank it takes 16 minutes....
| Is This Answer Correct ? | 7 Yes | 1 No |
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