Answer / guest

A tricky ONE.

Given 3 points are colinear. Hence, it is a straight line.

Hence area of triangle is 0.

Answer / manjunath ronad

By the co-ordination of A(e,p) B(2e,3p)
and C(3e,5p) are A(x1,y1),B(x2,y2) and C(x3,y3) respectively
then

Area of triangle=[(x1(y2-y3)+x2(y3-y1)+x3(y1-y2)/2]

=[(e(3p-5p)+2e(5p-p)+3e(p-3p)/2]
=0


Therefore in a given co ordinates area of triangle=0

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