12 members were present at a board meeting. Each member
shook hands with all of the other members before & after the
meeting.
How many hand shakes were there?
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Answer / guest
132
Think of it this way: the first person shakes hands with 11
people, the second person also shakes hands with 11 people,
but you only count 10, because the hand shake with the first
person was already counted. Then add 9 for the third person,
8 for the fourth, & so on.
66 hand shakes took place before & 66 after the meeting, for
a total of 132.
| Is This Answer Correct ? | 148 Yes | 12 No |
Answer / ajay maurya
For n nuimber of persons shaking hands with each other,
total no of handshakes are n(n-1)/2.
Hence for 12 people itis 12(12-1)/2= 66
Thus total handshakes = 2*66=132
| Is This Answer Correct ? | 93 Yes | 4 No |
Answer / raj
For n nuimber of persons shaking hands with each other,
total no of handshakes are n(n-1)/2.
Hence for 12 people itis 12(12-1)/2= 66
Thus total handshakes = 2*66=132
| Is This Answer Correct ? | 45 Yes | 2 No |
Answer / saurabh sukhija
For n nuimber of persons shaking hands with each other,
total no of handshakes are n(n-1)
Thus total handshakes =12(12-1)=132
| Is This Answer Correct ? | 17 Yes | 5 No |
Answer / tharvesh
132 bcoz the total count is 12
Ans:n(n-1)
12(12-1)
12*11
132 is the Ans
| Is This Answer Correct ? | 1 Yes | 1 No |
Answer / rahul
At first time handshake will be 11 and decrease this to 1 that the formula of sum of this sereis is=n(n+1)/2.
that n=11 put in formula
(11*(11+1)/2)=66
66+66=132 bcoz handshake will be two times
| Is This Answer Correct ? | 0 Yes | 2 No |
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