There are 9 coins. Out of which one is odd one i.e weight is
less or more. How many iterations of weighing are required
to find odd coin?
- 4 Answers
- 19105 Views
- Accenture, I also Faced
- E-Mail Answers
Answers were Sorted based on User's Feedback
Answer / vivek rai
Only 2 iterations required.
1- Take 6 coins and weigh 3 against 3
2- if it is equal then havier coin will in rest of 3 coin.
then we take 2 coins in rest of 3 coin and weight.
3- if it is eqal then rest 1 coin is havier.
| Is This Answer Correct ? | 31 Yes | 11 No |
Answer / devendra singh
there are maximum two iterations in which the odd coin can
be found out
firstly weigh 3-3 coins and then there are two possibilities:
if they turn out two be equal that means the odd coin is in
the remaining 3 coins and then we can weigh any two coins
from the remaining 3 coins and if they are equal the left
one is odd and if they are not equal the one which is less
heavy or more heavier according to the problem will be the
odd one..
in the second condition if the 3-3 coins weighed earlier are
not equal then then the side of 3 coins which is heavier or
lighter as described in the problem will be taken and and
two coins from that will be weighed and as said earlier the
odd one can b spotted ...so just two weighings required.
| Is This Answer Correct ? | 3 Yes | 1 No |
Answer / guest
It is always possible to find odd coin in 3 weighings and to
tell whether the odd coin is heavier or lighter.
1. Take 8 coins and weigh 4 against 4.
o If both are not equal, goto step 2
o If both are equal, goto step 3
2. One of these 8 coins is the odd one. Name the coins on
heavier side of the scale as H1, H2, H3 and H4. Similarly,
name the coins on the lighter side of the scale as L1, L2,
L3 and L4. Either one of H's is heavier or one of L's is
lighter. Weigh (H1, H2, L1) against (H3, H4, X) where X is
one coin remaining in intial weighing.
o If both are equal, one of L2, L3, L4 is lighter. Weigh L2
against L3.
? If both are equal, L4 is the odd coin and is lighter.
? If L2 is light, L2 is the odd coin and is lighter.
? If L3 is light, L3 is the odd coin and is lighter.
o If (H1, H2, L1) is heavier side on the scale, either H1 or
H2 is heavier. Weight H1 against H2
? If both are equal, there is some error.
? If H1 is heavy, H1 is the odd coin and is heavier.
? If H2 is heavy, H2 is the odd coin and is heavier.
o If (H3, H4, X) is heavier side on the scale, either H3 or
H4 is heavier or L1 is lighter. Weight H3 against H4
? If both are equal, L1 is the odd coin and is lighter.
? If H3 is heavy, H3 is the odd coin and is heavier.
? If H4 is heavy, H4 is the odd coin and is heavier.
3. The remaining coin X is the odd one. Weigh X against the
anyone coin used in initial weighing.
o If both are equal, there is some error.
o If X is heavy, X is the odd coin and is heavier.
o If X is light, X is the odd coin and is lighter.
| Is This Answer Correct ? | 7 Yes | 7 No |
Answer / saint
3 Iterations are required if you do not know if the odd
coin is lighter or heavier when you start. This is a nice
simple to follow process;
Divide coins into three piles of three, A, B & C
Weighing 1
-----------
Weigh piles A and B, and note which is the heaviest, or if
equal weight
Weighing 2
-----------
Weigh piles A and C, and note which is the heaviest or if
equal weight
If A does not equal both B and C, then A contains the odd
coin.
If A = C but does not equal B then B contains the odd
coin.
If A = B but does not equal C then C contains the odd
coin.
Having established which pile contains the odd coin, then
determine if it the odd pile is lighter or heavier by
looking at the results of the first two weighings
A = Odd pile
--------------
If A is the odd pile, then if it weighed less than B and C
in the first two weighings, then the odd coin is lighter,
else it is heavier
B = Odd Pile
------------------
Use the results of Weighing 1 and compare B with A. If A
was the lighter pile, then the odd coin is Heavier than the
rest, if A was heavier then the odd coin is Lighter
C = Odd Pile
------------------
Use the results of Weighing 2 and compare C with A. If A
was the lighter pile, then the odd coin is Heavier than the
rest, if A was heavier then the odd coin is Lighter
Weighing 3
-----------
Now take the pile that contains the odd coin, take two
coins out and weight them against one another
If the coins match, then the remaining coin is the odd coin
Else if the coins do not match, then if we are looking for
a lighter coin, then the lighter coin is odd, and if we are
looking for a heavier coin, then the heavier coin is odd!
-------------------------------------
| Is This Answer Correct ? | 5 Yes | 5 No |
How we get get 13*12=750 if any one knows how it is done plz answer it?
Taurus+pisces =scorpio,substitute the digits for the following letter to make the following addition true?
All of the tickets for 2 music concerts, X and Y, were either purchased or given away, and the ratio of X tickets to Y was 2 to 1. Of the total number of X tickets and Y tickets, what percentage was purchased? 1) The total number of X tickets and Y tickets, is 240. 2) Of the X tickets, exactly 60% were purchased, and of the Y tickets, exactly 80% were purchased. a) if statement (1) ALONE is sufficient, but statement (2) alone is not sufficient to answer the question. b) if statement (2) ALONE is sufficient, but statement (1) alone is not sufficient to answer the question. c) if BOTH statements (1) and (2) TOGETHER are sufficient to answer the question asked, but NEITHER statement ALONE is sufficient. d) if EACH statement ALONE is sufficient to answer the question asked. e) if statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data specific to the problem are needed.
Mark ate half of a pizza on Monday. He ate half of what was left on Tuesday and so on. He followed this pattern for one week. How much of the pizza would he have eaten during the week?
5 Answers Jindal Steel and Power,
Find the smallest number such that if its rightmost digit is placed at its left end, the new number so formed is precisely 50% larger than the original number.
Three neighbours are there. 1st one lends 2nd and 3rd that many no.of tractors that then already each had.After few months , 2nd lends to 1st and 3rd that many tractors then they had. After a few months 3rd lends to 1st and 2nd that many tractors then they had.Now each of them got 24. Find howmany they had initially?
rich man keeps me in pocket, poor men throws me away, children eat me, am a tamil word _u_ _e_ _l
9 Answers Adama Agricultural Solutions, Infosys, Mannar Company, Wipro,
On the shelf you have 10 identical bottles of identical pills (let?s say there?s a hundred pills in each bottle). However, one of those 10 bottles contains cheap knockoff pills. The only way to differentiate fake pills from real pills is the weight - while real pills weigh 1 g each, the knockoff pills are only 0.9 g. You have one scale that shows the exact weight (down to the mg) of whatever is weighed. How can you tell which bottle contains fake pills with just 1 weighing?
3 boys go to the restaurant. Their bill was 75 rs.. So they contributed 25 each. Manager then gives 5 rs back to the waiter and then waiter gave 3 rs back to them and put 2 rs into his pocket.. So their actual contribution is 24 because they got 1-1 rs back. so 24*3=72 and 2 rs into the waiter's pocket. so 74+2=74 where is 1 rs?
55 Answers College School Exams Tests, Garrison, Google, HCL, Jabong, Merlion, Rainbow Civil Engineers, Renault, TATA, Watair, Wipro,
There is a perfect sphere of diameter 40 cms. resting up against a perfectly straight wall and a perfectly straight floor i.e. the wall and the floor make a perfect right angle. Can a perfect sphere of diameter 7 cms. pass through the space between the big sphere, the wall and the floor? Support your answer with valid arguments. Don't submit just "Yes" or "No".
You have 9 marbles. 8 marbles weigh 1 ounce each, & one marble weighs 1.5 ounces. You are unable to determine which is the heavier marble by looking at them. You have a weighing scale that consists of 2 pans, but the scale is only good for 2 total weighings. How can you determine which marble is the heaviest one using the scale & in 2 weighings?
The minute and the hour hand of a watch meet every 65 minutes. How much does the watch lose or gain time and by how much?
English 
