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There are 9 coins. Out of which one is odd one i.e weight is
less or more. How many iterations of weighing are required
to find odd coin?
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Answer Posted / vivek rai
Only 2 iterations required.
1- Take 6 coins and weigh 3 against 3
2- if it is equal then havier coin will in rest of 3 coin.
then we take 2 coins in rest of 3 coin and weight.
3- if it is eqal then rest 1 coin is havier.
| Is This Answer Correct ? | 31 Yes | 11 No |
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