Question { 9142 }

What is the area of the triangle ABC with A(e,p) B(2e,3p)
and C(3e,5p)?

where p = PI (3.141592654)

Answer

By the co-ordination of A(e,p) B(2e,3p)
and C(3e,5p) are A(x1,y1),B(x2,y2) and C(x3,y3) respectively
then

Area of triangle=[(x1(y2-y3)+x2(y3-y1)+x3(y1-y2)/2]

=[(e(3p-5p)+2e(5p-p)+3e(p-3p)/2]
=0


Therefore in a given co ordinates area of triangle=0

Question { Karur Vysya Bank KVB, 5858 }

no.1-6 first is added the last 3 are subtracted , arrange
the no. so that each sum and difference give the same answer

Answer

3,2,1

Question { Infosys, 41366 }

what is Next number in the series is 1 , 2 , 4 , 13 , 31 ,
112 , ?

Answer

121