Answer / guest

There are total of 64 blocks on a chessboard. So 3 blocks
can be chosen out of 64 in 64C3 ways.

So the sample space is = 41664

There are 2 diagonal on chessboard each one having 8 blocks.
Consider one of them.

3 blocks out of 8 blocks in diagonal can be chosen in 8C3 ways.

But there are 2 such diagonals, hence favourables = 2 * 8C3
= 2 * 56 = 112

The require probability is

= 112 / 41664

= 1 / 372

= 0.002688

Answer / pradeep

(8c3+8c3)/64c3

Answer / anu

as total blocks are 64
and diagonals are 2 having 16 blocks
so 16c3/64c3
or
16!/64!

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