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You have 3 points labelled A, B and C. You then have another
3 points labelled 1, 2 and 3. The aim of the puzzle is to
connect point A with point 1, 2 and 3. Point B with point 1,
2 and 3 and point C with point 1, 2 and 3.

Now while connecting the points you have to follow one rule
- the lines cannot cross over each other.

Answers were Sorted based on User's Feedback



You have 3 points labelled A, B and C. You then have another 3 points labelled 1, 2 and 3. The aim ..

Answer / guest

A B C

1 2 3

PS : You can arrange the points in order as long as the
lines DO NOT cross over each other.

There is no solution to it, if you consider 2 dimensions. It
is impossible to join each of points A, B and C with points
1, 2 and 3 without lines crossing each other.

There is solution, if you consider 3 dimensions. Consider a
circular base and a line perpendicular to it passing from
the center. Now take any 3 points along the perimeter of the
circular base as points 1, 2 and 3. Similarly take any 3
points along the perpendicular line as points A, B and C.
Now it is quite simple to join each of points A, B and C
with points 1, 2 and 3 without any of the lines crossing
each other.

The other possible 3D structure is Pyramid. Take points 1, 2
and 3 as a vertices of the triangular base and points A, B
and C along the height of the Pyramid which is perpendicular
to the triangular base and passing through the apex.

Is This Answer Correct ?    8 Yes 1 No

You have 3 points labelled A, B and C. You then have another 3 points labelled 1, 2 and 3. The aim ..

Answer / amit jain

Yes its possible in 2D also.
Take one square. Mark two diagonal points as A & B and the
two diagonal points as 1 & 2.
Join the diagonals.
The crossing point of diagonals is point C as well as point 3.
(There is nowhere mentioned that points can not be overlapped)

So Here we have three points A, B and C connected with points
1, 2 and 3 without lines crossing each other.

1\------/A
| |
| 3,C |
| |
B/-----\2


:AJ_SGSITS

Is This Answer Correct ?    0 Yes 0 No

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