Answer / mohd. karim

KVAR - Reactive Power
It's Present only in Inductive load, i.e. X-mer, Motor, X-
mission Line..etc

And This power is required for generating Magnetic field in
inductive load.

Here, i want to explain some formuls

KVA = Sqrt((kw)^2 + (Kvar)^2)
Where , KVA = Apparant Power
KW= Actual Power
Kvar= Reactive Power

PF=KW/Kva = KW/(KW+Kvar) = COS$

1. If the value of kvar is more. it means PF is Less.
2. If the value of Kvar is zero. It means Unity PF (PF=1).
it means Apparant Power is Maxi. and over KW Loading is
Maxi.

--> Practically PF is not Unity (PF=1). its near about One.

For Reducing Kvar Demand We install Capacitor In Ckt.

Dis-Advantage (If Kvar is More)

1. less KW Loading(Low load Allow) in system.
2.Power Factor will Poor.
3.High current in system so Conductor & Cable size increase.
4.Electricity bill will more (Money Loss)

Answer / pradeep

kvar is nothing but the reactive power which is injected by
the capacitor bank. this power is similar to the real power
which generated by the generating unit.

by using capacitor bank we reduce losses like transmission
loss etc.,

advantages:
1. easy to convert the 2-phase into 3-phase.
2. reduce the losses and increase the efficiency.
3. it ensure upto 200Mhz

disadvantages:
1. it will inject the more power when bank is not necessary.
2. expensive due to connecting the capacitor bank.

substation+ plc system

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