Answer / gopal

i=v/R and R=rho.L/A . by analysing these fourmulas we find the size . here i is electric current in the conductor to flow or load current to flow . v is the voltage across the conductor , R is the resistance of the conductor . L is the length of the conductor ,rho is a constant of a material called specific resistance here the the material is the material of the conductor , A is the area of cross section of the conductor .

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