Answer / rama mohan parini

Require 3 Path test cases.

Test Case 1 - A is any value > 9 and C = 100 to check that
nothing is printed.

Test Case 2 - A is any value < 10 and C is > 100 to check
that Print A and
Print C is greater than A lines are printed

Test Case 3 - A is any value, and C is < 100 to check that
Print A ( only if A is < 10)
Print C is greater than A is printed.

We should use Cyclomatic complexity formula to calculate
number of paths easily

C = E - N + 2

Answer / hima bindu

Number of testcases required for branch coverage will be 2.

In branch coverage we need to check whether all the
branches are exercised.
Here we have 3 branches all If statements we need to
consider.They are A<10,C>100,C<100

Line 1 - Read(A,C)
Line 2 - If(A<10) then
Line 3 - Print A;
Line 4 - Endif
Line 5 - If(C>100)then
Line 6 - Print C is greater then A
Line 7 - else if(C<100) then
Line 8 - print C
Line 9 - End if

So take the values as follows
Testcase 1 : A=5 and C=120
For this set of values Line1 - Line6 are executed

Now for the Line7 - Line9 to be executed take the value of
c as less than 100
So Testcase 2 : A=5(can be any value as Line 2,3,4 are
already exercised in testcase1)and c=80
For this set of values Line7-Line9 will be exercised

Answer / madhu

3 cases would be required
as we need to exercise both positive and negative scenarios
of the 2 branches

Answer / ravo

two tests are required

Answer / kajal

answer is a.4

1 test case to check if system can read a and c
2 to check if a<10
3 to check if c is > 100 and < 100
to check if a and c are printed

Answer / varshab

Ans is 4 as there are two branches.For these two branches
we need to test for both true & false conditions. hence to
achieve 100% branch coverage we need to write 4 test cases.

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