If you started a business in which you earned Rs.1 on the
first day, Rs.3 on the second day, Rs.5 on the third day,
Rs.7 on the fourth day, & so on.
How much would you have earned with this business after 50
years (assuming there are exactly 365 days in every year)?
Answers were Sorted based on User's Feedback
Answer / genius
the ans is 333062500
50 yrs = 50 * 365 = 18250 days
the total earning=1+3+5+7+.......+n
where n=18250
so the sum of arithmetic progression is given by
s= n/2(2a+(n-1)d)
where
s = sum of progression
n = number of terms
a = value of first term
d = difference between 2 terms
so s=(18250/2)(2*1+18249*2)
which gives s=333062500
| Is This Answer Correct ? | 61 Yes | 7 No |
Answer / abhishek gupta
The correct ans. is 333062500
It's given that we work for 50 years, i.e., 50*365= 18250 days.
if we earn Rs.1 on the first day, Rs.3 on the second day,
Rs.5 on the third day & Rs.7 on the fourth day, means we
square the total no. of days to get the total money we
earned. E.g.
In 1 day, we earn Re.1 (squaring 1)
In 2 days, we earn Rs.3+1 (squaring 2) & so on......
So, squaring 18250 , the ans. is 333062500, i.e., we earn
Rs. 333062500 in 50 years= 18250 days.
My ans. has the shortest explanation & cud be called the
best ans. of all the above.
| Is This Answer Correct ? | 22 Yes | 3 No |
Answer / vinod gupta
Let n be the no. of days
Then (n*2)-1 gives us the amount that you earn for that many
days.
Since we need to find for 50 years and each year has 365 days
Thus, n = (365*50) = 18250
Therefore on 50 years you get,
(18250*2)-1 = 36500-1 = 36499
This is the amount you earn on 50 years.
But we need to find the total amount that we would earn
after 50 years.
For this we need to add the amount from day 1 till 50 years
i.e; 18250
Thus we have,
1 + 3 + 5 + 7 + 9 + ... + 36499 = 333062500
Thus after 50 years we have Rs.333,062,500
| Is This Answer Correct ? | 13 Yes | 1 No |
Answer / siddheshwar mali
he ans is 333062500
50 yrs = 50 * 365 = 18250 days
the total earning=1+3+5+7+.......+n
where n=18250
so the sum of arithmetic progression is given by
s= n/2(2a+(n-1)d)
where
s = sum of progression
n = number of terms
a = value of first term
d = difference between 2 terms
so s=(18250/2)(2*1+18249*2)
which gives s=333062500
Thanks for Marking this Answer
Answer / abhishek gupta
The correct ans. is 333062500
It's given that we work for 50 years, i.e., 50*365= 18250 days.
if we earn Rs.1 on the first day, Rs.3 on the second day,
Rs.5 on the third day & Rs.7 on the fourth day, means we
square the total no. of days to get the total money we
earned. E.g.
In 1 day, we earn Re.1 (squaring 1)
In 2 days, we earn Rs.3+1 (squaring 2) & so on......
So, squaring 18250 , the ans. is 333062500, i.e., we earn
Rs. 333062500 in 50 years= 18250 days.
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / lava
365*50=18250
sum of n odd no =npwr 2
1+2+3+....upto 18250 terms
so 18250pwr 2=333062500
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / ranjith naidu
let us consider first for 10 days = rs.19=x
next for 20 days =rs.39
and so on
it means for every 10 days itis x+20
in next step x will change that is now x=39
and so on
now in 50 years it will be
((50*365*19)/10)+20)=rs.34695
ans:rs 34695
| Is This Answer Correct ? | 6 Yes | 21 No |
Answer / navpreet singh
50 * 365 = 18250 days
(18250 * 2) - 1 = 36499
| Is This Answer Correct ? | 1 Yes | 16 No |
o,t,t,f,f,s,s,_,_ fill the remaining....and tell me on 9022881719
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