Interested to Buy Any Domain ? << Click Here >> for more details...
void main()
{
int i=1;
printf("%d%d%d",i,++i,i++);
}
Cau u say the output....?
- 24 Answers
- 69326 Views
- HCL, I also Faced
- E-Mail Answers
Answers were Sorted based on User's Feedback
Answer / subash
221
because it starts executing from right to left
so it first executes i++(the increment will happen when
entire printf statement is executed so now ++i which means
it is the pre incremant so now i becomes 2
| Is This Answer Correct ? | 2 Yes | 3 No |
Answer / kiran
The output will be 1 2 2...
First the assigned value of i(1) is printed. Then (++i) prints the Incremented value of i which is 2 will be printed.
Now as the Postfix operator only prints thhe value first and then increments...so the value of i is again 2..
| Is This Answer Correct ? | 4 Yes | 5 No |
Answer / we r the new inventors
the explanation above are also correct but think they are somewhat wrong because it was post increment of i.so value of i will become 2..
| Is This Answer Correct ? | 1 Yes | 2 No |
Answer / we are the new inventors
above answers are also right but i think they are somewhat wrong..because its a post increment of i so ans will become 2...
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / sums
The ans is obv 3 3 1...
The explanations given are also correct
For all those u r giving other answers without even giving the reason should at least run the program in "gcc" before writing anything
| Is This Answer Correct ? | 2 Yes | 4 No |
Answer / pratik
answer is 1 1 2 ..
it is an example of stack type ..
| Is This Answer Correct ? | 0 Yes | 4 No |
Write a program to accept two strings of Odd lengths. Then take all odd characters from one string and even characters from the other and concatenate and produce a string.
What is the code for following o/p * * * * * * * * * * * * * * * *
how tally is useful?
who was the present cheif governor of reserve bank of india
6 Answers State Bank Of India SBI,
how to convert decimal to hexadecimal without using arrays just loops
2. A student studying Information Technology at Polytechnic of Namibia is examined by coursework and written examination. Both components of assessment carry a maximum of 50 marks. The following rules are used by examiners in order to pass or fail students. a. A student must score a total of 40% or more in order to pass (total = coursework marks + examination marks) b. A total mark of 39% is moderated to 40% c. Each component must be passed with a minimum mark of 20/50. If a student scores a total of 40% or more but does not achieve the minimum mark in either component he/she is given a technical fail of 39% (this mark is not moderated to 40%) d. Grades are awarded on marks that fall into the following categories. Mark 100-70 69-60 59-50 49-40 39-0 Grade A B C D E Write a program to input the marks for both components (coursework marks out of 50 and examination marks out of 50), out put the final mark and grade after any moderation. [30]
Given that two int variables, total and amount, have been declared, write a loop that reads integers into amount and adds all the non-negative values into total. The loop terminates when a value less than 0 is read into amount. Don't forget to initialize total to 0. Instructor's notes: This problem requires either a while or a do-while loop.
what is run time error?
write the value of x and y after execution of the statements: int x=19,y; y=x++ + ++x; x++; y++;
#include<iostream.h> #include<stdlib.h> static int n=0; class account { int age,accno; float amt; char name[20]; public: friend void accinfo(account [] ,int); void create(); void balenq(); void deposite(); void withdrawal(); void transaction(account []); }; void account :: create() { static int acc=1231; accno=acc+n; cout<<"\n\tENTER THE CUSTOMER NAME : "; cin>>name; cout<<"\n\t ENTER THE AGE : "; cin>>age; cout<<"\n\t ENTER THE AMOUNT : "; cin>>amt; // if(amt<=500) // cout<<"\n\tAMOUNT IS NOT SUFFICIENT TO CREATE AN ACCOUNT..."; cout<<"\n\t YOUR ACCOUNT NUMBER : "<<accno<<endl; n++; } void accinfo(account cus[],int ch) { int no,flag=0; cout<<"\n\t\tENTER YOUR ACCOUNT NUMBER : "; cin>>no; for(int i=0;i<=n&&flag==0;i++) if(no==cus[i].accno) { flag=1; switch(ch) { case 2: cus[i].balenq(); break; case 3: cus[i].deposite(); break; case 4: cus[i].withdrawal(); break; case 5: cus[i].transaction(cus); break; default: cout<<"\n\t\tEND OF THE OPERATION"; exit(1); } } if(flag==0) cout<<"\n\t\tYOUR ACCOUNT DOES NOT EXIST..."<<endl; } void account :: balenq() { cout<<"\n\t\tCUSTOMER NAME : "<< name << endl; cout<<"\n\t\tBALANCE : "<< amt << endl; } void account :: deposite() { int damt; cout<<"\n\t\tCUSTOMER NAME : "<< name <<endl; cout<<"\n\t\tBALANCE : "<< amt <<endl; cout<<"\n\tENTER THE AMOUNT TO BE DEPOSITED : "; cin>>damt; amt+=damt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; } void account :: withdrawal() { int wamt; cout<<"\n\t\tCUSTOMER NAME : "<< name; cout<<"\n\t\tBALANCE : "<< amt; cout<<"\n\tENTER THE AMOUNT TO BE WITHDRAWN : "; cin>>wamt; if(amt-wamt>=500) { amt-=wamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt; } else cout<<"\n\tYOUR BALANCE IS TOO LOW FOR WITHDRAWAL..."<<endl; } void account :: transaction (account cus[]) { int no,tamt,flag=0; cout<<"\n\tENTER THE RECEIVER'S ACCOUNT NUMBER : "; cin>>no; cout<<"\n\t\t ENTER THE AMOUNT : "; cin>>tamt; for(int i=0;i<=n&&flag==0;i++) if(cus[i].accno==no) { flag=1; cus[i].amt+=tamt; amt-=tamt; cout<<"\n\t\tYOUR CURRENT BALANCE : "<<amt<<endl; cout<<"\n\t\t RECEIVER'S BALANCE : "<<cus[i].amt<<endl; } if(flag==0) cout<<"\n\tRECEIVER'S ACCOUNT NUMBER IS NOT AVALIABLE..."<<endl; } void main() { account cus[10]; int ch; do { cout<<"\n\t\t BANK ACCOUNT"; cout<<"\n\t\t ************\n"; cout<<"\n\t\t1.CREATE AN ACCOUNT"; cout<<"\n\t\t2.BALANCE ENQUIRY"; cout<<"\n\t\t3.DEPOSITE"; cout<<"\n\t\t4.WITHDRAWAL"; cout<<"\n\t\t5.TRANSACTION"; cout<<"\n\t\t6.EXIT\n\n"; cout<<"\n\t\tENTER YOUR CHOICE : "; cin>>ch; if(ch==1) cus[n].create(); else accinfo(cus,ch); }while(1); }
Write a C program to enter 10 integer numbers through one variable and count how many of them are even using while loop ?
when i use cout or cin call & then either << or >> .....it shows declaration syntax error...what should i do? cout<<"anything"; int a; cin>>a; return 0;
C C++ Errors 
