void main() { int i=1; printf("%d%d%d",i,++i,i++); } Cau u say th

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void main()
{
int i=1;
printf("%d%d%d",i,++i,i++);
}
Cau u say the output....?

Question Posted / mariaalex007

24 Answers
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void main() { int i=1; printf("%d%d%d",i,++i,i++); } Cau u say the output....?..

Answer / shanthi

122

Is This Answer Correct ?

2 Yes

3 No

void main() { int i=1; printf("%d%d%d",i,++i,i++); } Cau u say the output....?..

Answer / subash

221
because it starts executing from right to left
so it first executes i++(the increment will happen when
entire printf statement is executed so now ++i which means
it is the pre incremant so now i becomes 2

Is This Answer Correct ?

2 Yes

3 No

void main() { int i=1; printf("%d%d%d",i,++i,i++); } Cau u say the output....?..

Answer / kiran

The output will be 1 2 2...
First the assigned value of i(1) is printed. Then (++i) prints the Incremented value of i which is 2 will be printed.
Now as the Postfix operator only prints thhe value first and then increments...so the value of i is again 2..

Is This Answer Correct ?

4 Yes

5 No

void main() { int i=1; printf("%d%d%d",i,++i,i++); } Cau u say the output....?..

Answer / we r the new inventors

the explanation above are also correct but think they are somewhat wrong because it was post increment of i.so value of i will become 2..

Is This Answer Correct ?

1 Yes

2 No

void main() { int i=1; printf("%d%d%d",i,++i,i++); } Cau u say the output....?..

Answer / we are the new inventors

above answers are also right but i think they are somewhat wrong..because its a post increment of i so ans will become 2...

Is This Answer Correct ?

0 Yes

1 No

void main() { int i=1; printf("%d%d%d",i,++i,i++); } Cau u say the output....?..

Answer / sums

The ans is obv 3 3 1...
The explanations given are also correct
For all those u r giving other answers without even giving the reason should at least run the program in "gcc" before writing anything

Is This Answer Correct ?

2 Yes

4 No

void main() { int i=1; printf("%d%d%d",i,++i,i++); } Cau u say the output....?..

Answer / sam

first the initial value of i is 1
i++ is post decremented so,i++ must be 1

final value is " 1 2 1"

Is This Answer Correct ?

1 Yes

3 No

void main() { int i=1; printf("%d%d%d",i,++i,i++); } Cau u say the output....?..

Answer / ramya

OUTPUT:
1,2,1

Is This Answer Correct ?

0 Yes

2 No

void main() { int i=1; printf("%d%d%d",i,++i,i++); } Cau u say the output....?..

Answer / pratik

answer is 1 1 2 ..
it is an example of stack type ..

Is This Answer Correct ?

0 Yes

4 No

void main() { int i=1; printf("%d%d%d",i,++i,i++); } Cau u say the output....?..

Answer / ismail ns

1 1 2

Is This Answer Correct ?

1 Yes

8 No

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