Implement a function that returns the 5th element from the
end in a singly linked list of integers in one pass.
Answers were Sorted based on User's Feedback
Answer / amol b
int return_fifth_from_end()
{
int a[5],curr_ct=0;
struct node *p;
p=head;
while(p->next!=NULL)
{
a[curr_ct%5]=p->val;
p=p->next;
curr_ct++;
}
if(curr_ct>=5)
return a[(curr_ct-5)%5];
else
return -1;
}
| Is This Answer Correct ? | 8 Yes | 0 No |
Answer / abhijit annaldas
Sorry, it was my mistake.. previous answer was not correct.
Here is the corrected one...
node* getNthFromLast(node* head, int n)
{
int c=0;
node *nth=head;
node *pt=head;
while(pt!=NULL)
{
pt=pt->next;
c++;
//if c=n then nth node is already set to head.
if(c>n)
nth=nth->next;
}
if(c<n) //LL contains less than n nodes
return (*node)0;
else
return *nth;
}
Use it as..
fifth_node = getNthFromLast(head, 5);
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / tarun dhiraj
Consider:
struct Node
{
int data;
struct Node *next;
}*start;
void FIFTHFRMLAST()
{
struct Node *ptr;
ptr=start;
printf("\n");
/*Traverse elements of linked list till the 5th element from
the end of linked list*/
while(ptr->next->next->next->next->next!=NULL)
{
ptr=ptr->next;
}
printf("->%d",ptr->data);
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / abhijit annaldas
node* getNthFromLast(node* head, int n)
{
int c;
node *nth;
while(pt!=NULL)
{
pt=pt->next;
c++;
if(c>=n)
*nth=pt;
}
if(c<n) //LL contains less than n nodes
return (*node)0;
else
return *nth;
}
Use it as..
fifth_node = getNthFromLast(head, 5);
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / manesh nambiar
int return_fifth_from_end()
{
int i,j;
struct node *p,*q;
*p=HEAD_NODE;
for(i=0;i<4;i++)//will make p point to the 5th element
{
p=p->next;
if(p==NULL)
{
printf("List has less than 5 elements");
}
}
q=HEAD_NODE;
while(p!=NULL)
{
p=p->next;
q=q->next;
}
return(q->Value);
}
| Is This Answer Correct ? | 8 Yes | 7 No |
Answer / lly
I think both #1 & #2 are wrong. Because the code travels
the list in two passes not one pass.
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / jishu
Answer 6 is correct and well thought but there is a tiny
mistake.
the while loop should check upto the last node which it
doesn't and hence prints the wrong value ie. value of the
node before the fifth node from the end.
while(p!=NULL) would give the correct node.
Also while returning the value, decrementing curr_ct by 5 is
not really necessary.
return a[curr_ct%5]; would give the same value in all cases.
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / vignesh1988i
let us assume that we have created a linked lists ..... the
no. of nodes is say 15.
count=15;
printf("enter the node do you wann to look out :\n");
scanf("%d",&i);
if(i>count || i>=0)
printf("no node exists like this \n");
else
{
i=count-i;
view_node(i);
printf("%d",HEAD1->data);
}
getch();
}
void view_node(int i)
{
HEAD1=HEAD;
for(int k=1;k<i;k++)
HEAD1=->HEAD1->ptr;
}
| Is This Answer Correct ? | 2 Yes | 2 No |
Answer / gbohrn
int return_fifth_from_end()
{
int i,j;
struct node *p,*q;
*p=HEAD_NODE;
for(i=0;i<4;i++)//will make p point to the 5th element
{
p=p->next;
if(p==NULL)
{
printf("List has less than 5 elements");
}
}
q=HEAD_NODE;
while(p->next!=NULL)
{
p=p->next;
q=q->next;
}
return(q->Value);
}
| Is This Answer Correct ? | 5 Yes | 6 No |
Answer / a.eklare7
int fifth_element_last(node *head)
{
node *p;
int len=0;
p=head;
while(p->next!=NULL)
{
p=p->next;
len++;
}
p=head;
for(int i=1;i<=len-4;i++)
p=p->next;
return(p->data);
}
| Is This Answer Correct ? | 0 Yes | 1 No |
What is the right type to use for boolean values in c? Is there a standard type?
Why header file is used in c?
how to find the given number is prime or not?
What is the use of gets and puts?
What are c preprocessors?
write a “Hello World” program in “c” without using a semicolon?
What are derived data types in c?
Display names and numbers of employees who have 5 years or more experience and salary less than Rs.15000 using array of structures (name, number, experience and salary)
write a program to display the array elements in reverse order in c language
what will be the output of this program........ main() { int a=2,b=4,c=6; printf("%d"); } why it gives the value of third variable.
What is the use of the sizeof operator?
You have an array of n integers, randomly ordered with value 1 to n-1.The array is such that there is only one and one value occurred twice. How will you find this number?