write a program in c to read array check element is present or
not?
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Answer / tatukula
#include<stdio.h>
int main()
{
char array[10]={0,1,2,3,4,5,6,7,8,9};
int check;
int i,flag=0;
printf("enter number you want to check in array\n");
scanf("%d",&check);
for(i=0;i<=sizeof(array);i++)
{
if(array[i] == check)
{
flag = 1;
break;
}
}
if(flag)
printf("element is present in the array\n");
else
printf("element is not present in the array\n");
}
input: 4
output: element is present in the array
input: 45
output: element is not present in the array
| Is This Answer Correct ? | 5 Yes | 0 No |
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