Implement a function that returns the 5th element from the
end in a singly linked list of integers in one pass.
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Answer Posted / vignesh1988i
let us assume that we have created a linked lists ..... the
no. of nodes is say 15.
count=15;
printf("enter the node do you wann to look out :\n");
scanf("%d",&i);
if(i>count || i>=0)
printf("no node exists like this \n");
else
{
i=count-i;
view_node(i);
printf("%d",HEAD1->data);
}
getch();
}
void view_node(int i)
{
HEAD1=HEAD;
for(int k=1;k<i;k++)
HEAD1=->HEAD1->ptr;
}
| Is This Answer Correct ? | 2 Yes | 2 No |
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a number whose only prime factors are 2,3,5, and 7 is call humble number,,write a program to find and display the nth element in this sequence.. sample input : 2,3,4,11,12,13, and 100.. sample output : the 2nd humble number is 2,the 3rd humble number is 3,the 4th humble number is ,the 11th humble number is 12, the 12th humble number is 14, the 13th humble number is 15, the 100th humble number is 450.
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