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write a program that will accept two integers and will implement division without using the division operator if the second value is an odd number and will implement multiplication without using multiplication operator if the second value is an even number.
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Answer / yogi patel
//Yogi patel
#include<conio.h>
#include<stdio.h>
void main()
{
int a,b,ans,i;
clrscr();
printf("Enter first number :->> ");
scanf("%d",&a);
printf("Enter second number :->> ");
scanf("%d",&b);
if(b%2==0)
{
ans=a;
printf("Division perform");
for(i=0; i<(a/2); i++)
{
ans=ans-1;
}
printf("\n\nAns is :- %d",ans);
}
else
{
ans=0;
printf("Multiplication perform");
for(i=0; i<b; i++)
{
ans=ans+a;
}
printf("\n\nAns is :- %d",ans);
}
getch();
}
| Is This Answer Correct ? | 1 Yes | 0 No |
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