write a program that will accept two integers and will implement division without using the division operator if the second value is an odd number and will implement multiplication without using multiplication operator if the second value is an even number.
- 1 Answers
- 3941 Views
- I also Faced
- E-Mail Answers
Answer / yogi patel
//Yogi patel
#include<conio.h>
#include<stdio.h>
void main()
{
int a,b,ans,i;
clrscr();
printf("Enter first number :->> ");
scanf("%d",&a);
printf("Enter second number :->> ");
scanf("%d",&b);
if(b%2==0)
{
ans=a;
printf("Division perform");
for(i=0; i<(a/2); i++)
{
ans=ans-1;
}
printf("\n\nAns is :- %d",ans);
}
else
{
ans=0;
printf("Multiplication perform");
for(i=0; i<b; i++)
{
ans=ans+a;
}
printf("\n\nAns is :- %d",ans);
}
getch();
}
| Is This Answer Correct ? | 1 Yes | 0 No |
Why doesn't C have nested functions?
Why do u use # before include in a C Progam?
How are portions of a program disabled in demo versions?
Explain what are the advantages and disadvantages of a heap?
Explain Function Pointer?
1,4,8,13,21,30,36,45,54,63,73,?,?.
10 Answers AMB, Franklin Templeton,
What would the following code segment printint k = 8;docout << "k = " << k << " ";while k++ < 5; a) 13 b) 5 c) 8 d) pointers
What is #include stdio h?
HOW TO HANDLE EXCEPTIONS IN C
How we add our function in liabrary as liabrary function. Exp. we want use our int factorical(int); function as int pow(int,int); function working in math header file.
print the palindrome numbers in between 0 to n
What is the result main() { char c=-64; int i=-32 unsigned int u =-16; if(c>i){ printf("pass1,"); if(c<u) printf("pass2"); else printf("Fail2");} else printf("Fail1); if(i<u) printf("pass2"); else printf("Fail2") } a)Pass1,Pass2 b)Pass1,Fail2 c)Fail1,Pass2 d)Fail1,Fail2 e)none
C 
