write a program to swap Two numbers without using temp variable.
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Answer / insane programmer
#include<stdio.h>
#include<conio.h>
void main()
{
int a=100, b=30;
clrscr();
a = a+b;
b = a-b;
a = a-b;
printf("Swapping without using third variable (using + and -).\n\n");
printf("Value of a=%d and b=%d.", a,b);
getch();
}
you can get more example here http://rajkishor09.hubpages.com/_eknow/hub/How-to-swap-two-numbers-without-using-third-temp-variable
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / george washington
Suppose:
x=1
y=3
Redefine:
x=x+y; //Or, x=1+3=4 and
y=x-y; // y=4-3=1 and
x=x-y; // x=4-1=3
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / ankit
a=a+b;
b=a-b;
a=a-b;
example int a=2;int b=3
put a=2 & b=3
a=2+3;
b=5-3;
a=5-2;
a=3;
b=2;
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / amar
void main()
{
int a,b;
printf("enter the two numbers");
scanf("%d%d",&a,&b);
a^=b^=a^=b;
printf("%d%d",a,b);//swapped no
}
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / tchoephel
#include<stdio.h>
#include<conio.h>
void main()
{
int a,b;
printf("enter two nos A and B\n");
scanf("%d%d",a,b);
printf("before swaping A=%d\n B=%d\n",a,b);
a=a+b:
b=a-b;
a=a-b;
prinf("after swaping A=%d\n B=%d\n",a,b);
getch();
}
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / akash
#include<stdio.h>
#include<conio.h>
void main()
{
int a,b;
clrscr();
printf("enter the value a & b");
scanf("%d%d",&a,&b);
a=a+b;
b=a-b;
a=a-b;
printf("interchange in a & b =%d%d",a,b);
getch();
}
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / ijagz
#include<conio.h>
#include<stdio.h>
int main()
{
int a,b;
printf("Enter the first number\n");
scanf("%d",&a);
printf("Enter the second number\n");
scanf("%d",&b);
printf("your answer is %d %d",b,a);
getch();
return 0;
}
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / rani
#include<stdio.h>
#include<conio.h>
void main()
{
int a,b;
printf ("enter the values to a & b");
scanf("%d%d",&a,&b);
a=a+b;
b=a-b;
a=a-b;
printf("%d%d",a,b);
}
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / jaspreet singh
hey prasanna the program you hv writen is correct but this
method fails when we give the input as a=32767 and b=1
the correct method is
a^=b^=a^=b
or
a=a^b;
b=a^b;
a=a^b;
it will always return the correct answer even if the input
is a=32767 and b=1...............
| Is This Answer Correct ? | 17 Yes | 17 No |
Answer / shubham agarwal
the answer is simple
a=a*b;
b=a/b;
a=a/b;
this is one of the few possible ways to swap
simple app. of +,- can also brong the result
by
shubham agarwal
shubham.agarwal363@yahoo.com from NIT Srinagar
| Is This Answer Correct ? | 8 Yes | 8 No |
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