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what is the output of the following program?
main()
{
int c[]={2,8,3,4,4,6,7,5};
int j,*p=c,*q=c;
for(j=0;j<5;j++)
{
printf("%d",*c);
++q;
}
for(j=0;j<5;j++)
{
printf("%d",*p);
++p;
}
}
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Answer / vignesh1988i
2222228344...
the above code can be remodified as :
printf("%d",*q); in first printf statement to get the same
output for both printf statements
thank u
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / ashwin kumar
output is 2222228344
in loop 1
as we know that array variable contain the base address of
the array
*c means we are trying to print the value of contained in
the base address which is not changed in the loop
note we can't change the base address of the array that is
we can't do 'c++'
as in loop for 5 times contain of the base address will be
printed as
22222
in loop 2
in assigned base address of the array to pointer p
here we are printing the contain of address stored in p and
increment the value of p ( that is pointing to the next
element of the array )
so we will get output for 2nd loop is
28344
overall answer is
2222228344
if any wroung in my aswer plz info me at
molugu.ashwin@gamil.com
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / abhradeep chatterjee
2222228344 will be the answer. I think everybody answered
before me is correct.
| Is This Answer Correct ? | 1 Yes | 0 No |
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