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A person goes 4/5 of his usual speed reaches 10 min late to
his destinaton, time taken?
- 7 Answers
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Answer / teja
Answer:50 min
explanation:
speed=distance/time
in both cases distance is same.
s1*t1=s2*t2
s*t=(4s/5)*(t+10)
t=40 min
but we want total time means 10 min late
40+10=50 min
| Is This Answer Correct ? | 29 Yes | 18 No |
Answer / pradeep
We know speed × time = distance, so ((4/5)×s)×(t+10)=D
On solving above equation we get
4/5×st+4/5s×10=D
4st+40s=5st. [ Since D=S×T]
(4t+40)= 5t
40=5t-4t
t=40 minutes.
| Is This Answer Correct ? | 9 Yes | 0 No |
Answer / ramesh naidu
ans is:50 min....4/5th of his usual speed leads 10 min
late....means..1/5th of his speed equals
10min...1/5*speed=10->50 min...
| Is This Answer Correct ? | 14 Yes | 6 No |
Answer / rani t c
let a person's usual speed be x km/min
let the distance be d km
given (d/(4 x/5))-(d/x)=10
when we solve this equation we will get d=40 x
t=?
t=d/(4 x/5)=(40 x/(4 x/5))=(5*40)/4=50
answer is 50 min
| Is This Answer Correct ? | 0 Yes | 2 No |
Answer / deniro
speed is inversely proportional to time
ANS:50 min
| Is This Answer Correct ? | 3 Yes | 6 No |
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