A person goes 4/5 of his usual speed reaches 10 min late to his destinaton, tim

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A person goes 4/5 of his usual speed reaches 10 min late to
his destinaton, time taken?

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A person goes 4/5 of his usual speed reaches 10 min late to his destinaton, time taken? ..

Answer / kl

50 min

Is This Answer Correct ?

34 Yes

11 No

A person goes 4/5 of his usual speed reaches 10 min late to his destinaton, time taken? ..

Answer / teja

Answer:50 min
explanation:
speed=distance/time
in both cases distance is same.
s1*t1=s2*t2
s*t=(4s/5)*(t+10)
t=40 min
but we want total time means 10 min late
40+10=50 min

Is This Answer Correct ?

29 Yes

18 No

A person goes 4/5 of his usual speed reaches 10 min late to his destinaton, time taken? ..

Answer / pradeep

We know speed × time = distance, so ((4/5)×s)×(t+10)=D
On solving above equation we get
4/5×st+4/5s×10=D
4st+40s=5st. [ Since D=S×T]
(4t+40)= 5t
40=5t-4t
t=40 minutes.

Is This Answer Correct ?

9 Yes

0 No

A person goes 4/5 of his usual speed reaches 10 min late to his destinaton, time taken? ..

Answer / ramesh naidu

ans is:50 min....4/5th of his usual speed leads 10 min
late....means..1/5th of his speed equals
10min...1/5*speed=10->50 min...

Is This Answer Correct ?

14 Yes

6 No

A person goes 4/5 of his usual speed reaches 10 min late to his destinaton, time taken? ..

Answer / rani t c

let a person's usual speed be x km/min
let the distance be d km
given (d/(4 x/5))-(d/x)=10
when we solve this equation we will get d=40 x
t=?
t=d/(4 x/5)=(40 x/(4 x/5))=(5*40)/4=50
answer is 50 min

Is This Answer Correct ?

0 Yes

2 No

A person goes 4/5 of his usual speed reaches 10 min late to his destinaton, time taken? ..

Answer / deniro

speed is inversely proportional to time

ANS:50 min

Is This Answer Correct ?

3 Yes

6 No

A person goes 4/5 of his usual speed reaches 10 min late to his destinaton, time taken? ..

Answer / kumar

5 min

Is This Answer Correct ?

2 Yes

9 No

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