A person goes 4/5 of his usual speed reaches 10 min late to
his destinaton, time taken?
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Answer Posted / pradeep
We know speed × time = distance, so ((4/5)×s)×(t+10)=D
On solving above equation we get
4/5×st+4/5s×10=D
4st+40s=5st. [ Since D=S×T]
(4t+40)= 5t
40=5t-4t
t=40 minutes.
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