Answer / akhilesh singh(m.c.a-iisem ois

main()
{
int i,j=2,ch=0;
clrscr();
printf("\nENTER ANY NUMBER");
scanf("%d",&i);
while(j<=i/2)
{
if(i%j==0)
{
printf("%d IS NOT PRIME",i);
ch=1;
break;
}
else
{
j++;
}
}
if(ch==0)
{
printf("%d IS PRIME",i);
}
}

Answer / venkat reddy

#include<stdio.h>
main()
{
int i,n,count=0;
printf("enter a no.");
scanf("%d",&n);
for(i=2;i<n;i++)

{
if(n%i==0)
{
count++;
}
}
if(count>1)
{
printf("not prime no.");

}
else
printf("prime");
}

Answer / vasanth

This program is to check a given number is prime or not
(or) list the prime numbers in a given no.

For example, the user enter the no is 50. the program is
list the prime numbers in 50.

Answer / vinay tiwari

try this u can find out all prime number between 2 and any
number entered by user .i write code in c# language but
concept remain same in any language.
using System;
using System.Collections.Generic;
using System.Text;

namespace ConsoleApplication23
{
class Program
{
static void Main(string[] args)
{
int i=2, j, rem;
while (i <= 100)
{
for (j = 2; j < i; j++)
{
rem = i % j;
if (rem == 0)
break;
}
if (i == j)
Console.WriteLine(i);
i++;
}
}
}
}

Answer / priyanka chauhan

// prime no series. //
#include<stdio.h>
#include<conio.h>
void main()
{
int i,j,n;
clrscr();
printf("Enter the no: ");
scanf("%d",&n);
printf("\n");
for(i=1;i<=n;i++)
{
for(j=2;j<=i-1;j++)
{
if(i%j==0)
break;
}
if(j==i)
printf("%d ",j);
}
getch();
}

Answer / naveen reddy

This is written in PL/SQL: TO check wether given number is prime or not

DECLARE
i number:=&i;
j number:=2;
ch number:=0;
BEGIN
WHILE(j<=i/2) loop

if mod(i,j)=0 then
dbms_output.put_line('not prime');
ch:=1;
exit ;
else
j:=j+1;
end if;
end loop;

if ch=0 then
dbms_output.put_line('prime number');
end if;
end;

Answer / sham

int main()
{
int i,j,n,f=0;
printf("Enter the length\n");
scanf("%d",&n);
for(i=2;i<=n;i++)
{
for(j=2;j<i;j++)
{
if((i%j)==0)
{
f=1;
break;
}
f=0;
}
if(f==0)
printf("%d ",i);
}
}

Answer / gnanasekaran

int main()
{
int i,j,n,f=0;
printf("Enter the length\n");
scanf("%d",&n);
for(i=2;i<=n/2;i++)
{
for(j=2;j<i;j++)
{
if((i%j)==0)
{
f=1;
break;
}
f=0;
}
if(f==0)
printf("%d ",i);
}
}

Answer / arfu

#include<stdio.h>

int main()
{
int c,i,n;
c=0;
scanf("%d",&a);
for(i=2;i<a;i++)
if (n%i==0)
{
c=1;break;
}
if(c!=1)`("prime");
else printf ("not a prime");
}

Answer / pritam neogi

#include<stdio.h>
#include<conio.h>
void main()
{
int no,i,count=0;
clrscr();
printf("enter the no");
scanf("%d",&no);
for(i=1;i<=no;i++)
{
if(no%i==0)
{
count=count+1;
}
}
if(count<=2)
{
printf("this is prime no");
}
else
{
printf("this is not prime");
}
getch();
}

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0 Answers  

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