Answer / nitesh sanwal

#include<stdio.h>
#include<math.h>
void main()
{
int n,i,prime=1;
printf("input the numbers");
scanf("%d",&n);
for(i=2;i<=sqrt(n);i++)
if(n%i==0)
{
prime=0;
break;
}
if(prime)
printf("%d is a prime number",n);
else
printf("%d is a not a prime number",n);
}

Answer / shubhanshu pandey

main()
{
int a,c=0,i,n;
printf("enter the number to be checked");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
a=n%i;
if(a=0)
{
c=c+1;
}
}
if (c=2)
{ printf("the given number is prime"); }
else
printf("the given number is not prime");
}

Answer / vijay bharti

#include<stdio.h>
#include<conio.h>

void main()
{
int num,i,count=0;
clrscr();
for(num=1;num<=300;num++)
{
for(i=2;i<=num/2;i++)
{
if(num%i!=0)
count=count+1;
}

}

printf("number of prime numbers between 1 to 300 are : %d",count);
getch();
}

Answer / umesh prajapati

/* find the number is prime or not prime. umesh prajapati*/
#include<stdio.h>
#include<conio.h>
void main()
{
int n,c,r;
clrscr();
printf("ENTER THE VALUE");
scanf("%d",&n);
if(n==2)
printf("THE NUMBER IS CO-PRIME");
else
{
c=2;
while(c<n)
{
r=n%c;
if(r==0)
{
printf("GIVEN NUMBER IS NOT PRIME");
break;
}
c++;
}
if(r>0)
printf("GIVEN NUMBER IS PRIME");

}
getch();
}

Answer / karthik

#include<stdio.h>
#include<conio.h>
void main()
{
int n,c=0,i;
clrscr();
printf("enter any number");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
if(n%i==0)
c++;
}
(c==2)? printf("%d is a prime number",n):
printf("%d is not a prime number",n);
getch();
}

Answer / sudesh kumar

#include<iostream.h>
#include<conio.h>
void main()
{
int no;
cout<<"enter a no";
cin>>no;
for(i=2;i<no;i++)
{
r=no%i;
if(r==0)
{
p==0;
break;
}}
if(p==1)
{
cout<<"prime no";
}
else
{
cout<<"note prime";
}
getch();
}

Answer / biswa

void main()
{
int i=2;
int count=0;
int n;
printf("enter a no");
scanf("%d",&n);
for(i=2;i<n/2;i++)
{
if(n%i==0)
{
count++;
}
if(count>1)
{
prinf("prime");
else
printf("not prime");
}

Answer / felix c. intelegando

#include<stdio.h>
#include<conio.h>


int main(void)
{
int i,n,count=0;
printf("Enter Number: ");
scanf("%d",&n);
for(i=2;i<n;i++)

{
if(n%i==0)
{
count++;
}
}
if(count>1)
{
printf("Not Prime ");

}
else
printf("Prime");

getch();
return 0;
}

Answer / chinnakannasabari

#include <stdio.h>


int main (void)
{
int i, nb, count, test;
test = count = 0;
printf ("enter integer: ");
if (scanf ("%d", &nb) != 1)
return -1;

for (i = 2; i < nb; i++, count++)
if (nb % i == 0)
test = 1;
if (!test)
printf ("%d prime number, number of iterations = %dn",
nb, count);
else
printf ("%d is not a prime number, number of iterations
= %dn", nb,count);
return 0;
}

Answer / sachin 12

#include<stdio.h>
#include<conio.h>
void main()
{
int num,i=2,f=0,j;
printf("\n enter any number");
scanf("%d",&num);
a=num;
while(i<num)
{
if(num%i==0)
{
f=1
break;
}
i++;
}
if(f==i)
{
printf("\n the number is not prime");
}
else
{
printf(""\n the number is prime");
}
getch();
}

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