Answer / pritam neogi

#include<stdio.h>
#include<conio.h>
void main()
{
int no,i;
clrscr();
printf(" Enter the Number U want to check:");
scanf("%d",&no);
i=2;
while(i<=no-1)
{
if(no%i==0)
{
printf(" %d is not Prime number",no );
// break;
}
i=i+1;
}
if(no==i)
printf("%d is a prime Number",no);
getch();
}

Answer / arafat buet

#include<stdio.h>
int main()
{
int i,n,r;
printf("enter any number:");
scanf("%d",&n);
if(n==1)
printf("not prime\n");
for(i=2;i<n;i++)
{
r=n%2;
if(r==0)
{
printf("\nnot prime\n");
break;
}
}
if(i==n)
printf("prime\n");
return 0;
}

Answer / tayyab ali

write the program to print prime numbers from 1 to 1000?

Answer / karthik

#include<stdio.h>
#include<conio.h>
void main()
{
int n,flag;
clrscr();
printf("\n Enter prime no\n");
scanf("%d",&n);
for(int i=2;i<=n/2;i++)
{
if(n%i==0)
{
flag=0;
break;
}
}
if(flag==0)
printf("\n%d is not prime",n);
else
printf("\n %d is prime",n);
getch();
}

Answer / paartha

include<stdio.h>
#include<conio.h>

void main()
{
int a,i , b,flag=0,no;
clrscr();

for(no=2;no<100;no++)
{
for(i=2;i<no;i++)
{
b=no%i;
if(b==0)
{
flag=1;
break;
}
else
{
flag=0;
}
}
if(flag!=1)
{
printf("\n%d",no);
}
}

getch();
}

Answer / paps

#include<stdio.h>
void main()
{
int a=1,i,j,b,n;
printf("enter the range\n");
scanf("%d",&n);
printf("prime number series between 1 to %d:n");
printf("%d",a);
while(i<=n)
{
for(j=2;j<i;j++)
{
b=i%j;
if(b==0)
break;
}
if(i==j)
printf("%d",i);
i++;
}
getch();
}

Answer / kiran

#include<iostream>
#include<stdio.h>
#include<conio.h>
using namespace std;
int main()
{
int tn=1,c=0,flag=0;;
cin>>tn;
for(int i=3; c!=tn;i++)
{for(int j=2;j<i;j++)
{
if(i%j==0){

flag=0; break;}
else flag=1;
}
if(flag)
{c++;
printf("%d,",i);
}
}
getch();
return 0;
}

Answer / china

Find all primes not larger than N.
I think it is the most efficient algorithm to find all
primes no larger than N.

int main(void)
{
int i,j, N;
int *pPrimes;
int nPrimes, is_prime;
printf("Input N:");
scanf("%d", &N);

pPrimes = new int [N/2];
nPrimes = 0;
for(i = 2; i<=N; i++)
{
is_prime = 1;
for(j=0;j<nPrimes; j++)
if (i%pPrimes[j] == 0)
{
is_prime = 0; break;
}
if (is_prime)
{
pPrimes[nPrimes++] = i;
}
}

printf("%d primes found less than %d:\n", nPrimes, N);
for (i=0; i< nPrimes; i++)
printf("%d ", pPrimes[i]);

}

Answer / pratibha

#include<stdio.h>
#include<conio.h>
void main()
{
int no,i,count=0;
clrscr();
printf("enter the no");
scanf("%d",&no);
for(i=1;i<=no;i++)
{
if(no%i==0)
{
count=count+1;
}
}
if(count<=2)
{
printf("this is prime no");
}
else
{
printf("this is not prime");
}
getch();
}

Answer / jassneet anand

import java.*;

class prime
{
public static void main(String args[])
{
int number=__;//"you wish to check ";
int flag=0;
for(i=2;i<=(int)(Math.sqrt(number));i++)
{
if(number%i==0)
{
System.out.println("Not a Prime Number");
flag=1;
break;
}
}
if(flag==0)
System.out.println("Prime Number");
}
}

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